Problem 5
Question
Find any points of discontinuity for each rational function. $$ y=\frac{x^{2}+5 x+6}{x^{2}+6 x+9} $$
Step-by-Step Solution
Verified Answer
The function \(y=\frac{x^{2}+5x+6}{x^{2}+6x+9}\) is discontinuous at \(x = -3\).
1Step 1: Identify the Denominator of the Function
The denominator of the given function is \(x^{2}+6x+9\). This is the part of the function that will determine any points of discontinuity.
2Step 2: Set the Denominator Equal to Zero
We set the denominator equal to zero to find which values of x make the function undefined: \(x^{2}+6x+9 = 0\)
3Step 3: Solve the Equation for x
Solve the equation for the variable \(x\). The equation is a quadratic equation and can be factored to \((x+3)^2 = 0\). When this equation is solved, the solution for \(x\) is \(-3\).
4Step 4: Identify the Points of Discontinuity
The points of discontinuity of the function are the values of x where the function is undefined. With a solution of -3 from the previous step, it indicates that the function is discontinuous at \(x = -3\).
Key Concepts
Understanding Points of DiscontinuityIntroduction to Rational FunctionsSolving Quadratic Equations
Understanding Points of Discontinuity
Points of discontinuity occur in a function when there are certain values of the variable for which the function is not defined. In rational functions, this happens when the denominator is equal to zero. Since division by zero is undefined, these particular x-values cause the function to "break" or be discontinuous.
To find these points in a rational function, follow these simple steps:
To find these points in a rational function, follow these simple steps:
- Identify the denominator.
- Set the denominator equal to zero.
- Solve for x to find the point(s) of discontinuity.
Introduction to Rational Functions
Rational functions are fractions involving polynomials in the numerator and the denominator. A function becomes rational when it takes the form \( \frac{P(x)}{Q(x)} \), where both \( P(x) \) and \( Q(x) \) are polynomials. These functions can have interesting behaviors such as asymptotes and discontinuities.
Since rational functions can be complex, it's crucial to examine them carefully:
Since rational functions can be complex, it's crucial to examine them carefully:
- Look at both numerator and denominator.
- Check for factors that might cancel each other.
- Determine where the function is undefined.
Solving Quadratic Equations
The techniques used to solve quadratic equations are essential in finding the points of discontinuity in rational functions. A quadratic equation generally looks like \( ax^2 + bx + c = 0 \), and can often be factored or solved using the quadratic formula.
In our problem:
In our problem:
- The quadratic we solved was \( x^2 + 6x + 9 = 0 \).
- This can be factored into \((x+3)^2 = 0\).
- Solving this gives a repeated solution: \( x = -3 \).
Other exercises in this chapter
Problem 5
Solve each equation. Check each solution. $$ \frac{3}{x+1}=\frac{1}{x^{2}-1} $$
View solution Problem 5
Simplify each rational expression. State any restrictions on the variable. $$ \frac{2 x+10}{x^{2}+10 x+25} $$
View solution Problem 5
Find the least common multiple of each pair of polynomials. \(x^{2}-1\) and \(x^{2}+2 x+1\)
View solution Problem 5
Draw a graph of each function. Describe properties of the graph. \(y=\frac{-3}{x}\)
View solution