Problem 5
Question
Fill in the blanks. To factor \(a b+6 a+2 b+12\) by ____, we begin by factoring out \(a\) from the first two terms and 2 from the last two terms.
Step-by-Step Solution
Verified Answer
Factor by grouping to get \((a + 2)(b + 6)\).
1Step 1: Identify Part I Terms
The first part of the expression is \(ab + 6a\). Identify \(a\) as a common factor in these terms.
2Step 2: Factor Out Part I
Factor \(a\) out of the terms \(ab + 6a\) to get \(a(b + 6)\).
3Step 3: Identify Part II Terms
The second part of the expression is \(2b + 12\). Identify \(2\) as a common factor in these terms.
4Step 4: Factor Out Part II
Factor \(2\) out of the terms \(2b + 12\) to get \(2(b + 6)\).
5Step 5: Recognize Common Binomial Factor
Both factored parts contain the common binomial factor \((b + 6)\).
6Step 6: Perform Final Factoring
Combine the common factor \((b + 6)\) from the two parts to write the expression as \((a + 2)(b + 6)\). Thus, the expression is factored completely.
Key Concepts
Common FactorsBinomial ExpressionsDistributive Property
Common Factors
When working with algebraic expressions, one of the key skills is identifying common factors. This means finding a number or variable that is present in multiple terms of the expression.
In our exercise, the expression is divided into two parts: \(ab + 6a\) and \(2b + 12\).
This process simplifies the expression and is a crucial step in solving and simplifying algebraic problems.
In our exercise, the expression is divided into two parts: \(ab + 6a\) and \(2b + 12\).
- Observe that both terms in \(ab + 6a\) share \(a\) as a common factor.
- In \(2b + 12\), the number \(2\) is the common factor in these terms.
This process simplifies the expression and is a crucial step in solving and simplifying algebraic problems.
Binomial Expressions
In algebra, a binomial expression is a polynomial with precisely two terms. In this exercise, a common binomial expression is found in the parentheses after factoring out the common numbers in both parts.
After factoring, the expression becomes \(a(b + 6) + 2(b + 6)\). Notice the binomial \((b + 6)\) is present in both terms.
This leads to a more compact and manageable form of the original expression.
After factoring, the expression becomes \(a(b + 6) + 2(b + 6)\). Notice the binomial \((b + 6)\) is present in both terms.
- Binomials can be easily identified by their format: two terms connected by a plus or minus sign.
- Understanding how to manipulate binomials is crucial for successful factoring and algebraic simplification.
This leads to a more compact and manageable form of the original expression.
Distributive Property
The distributive property is a fundamental tool in algebra, allowing you to multiply a single term across terms inside a parenthesis. It is expressed as \(a(b + c) = ab + ac\). In factoring, this property works in reverse.
Once you have the factored terms such as \(a(b + 6)\) and \(2(b + 6)\), you can use the distributive property to combine them using their common binomial factor \((b + 6)\).
Once you have the factored terms such as \(a(b + 6)\) and \(2(b + 6)\), you can use the distributive property to combine them using their common binomial factor \((b + 6)\).
- The common binomial \((b + 6)\) can be factored out of both, resulting in \((a + 2)(b + 6)\).
- This step showcases the distributive process being reversed, where factors are brought together instead of spread apart.
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