Problem 5
Question
Exer. 1-50: Solve the equation. $$ 3|x+1|-2=-11 $$
Step-by-Step Solution
Verified Answer
No solution, since absolute values can't be negative.
1Step 1: Isolate the Absolute Value
First, we need to isolate the absolute value on one side of the equation. We start with the equation:\[3|x+1|-2=-11 \]Add \(2\) to both sides of the equation:\[3|x+1| = -11 + 2 \] Which simplifies to:\[3|x+1| = -9\]
2Step 2: Divide to Fully Isolate the Absolute Value
Next, divide both sides of the equation by 3 to solve for \(|x+1|\):\[|x+1| = \frac{-9}{3} \]Simplifying gives:\[|x+1| = -3 \]
3Step 3: Analyze the Absolute Value Situation
An absolute value expression is always non-negative, meaning \(|x+1|\) cannot be negative. Since \(|x+1|\) equals \(-3\), this situation is impossible, indicating there is no real value for \(x\) that satisfies this equation.
Key Concepts
Solving Absolute Value EquationsUnderstanding AlgebraIsolating Terms
Solving Absolute Value Equations
Solving equations involving absolute values can seem tricky at first. But, once you get the hang of the process, it becomes much more manageable. Absolute value equations like the one given can have two possible interpretations because the absolute value of a number is its distance from zero on the number line, always resulting in a non-negative value.
When dealing with an absolute value equation such as \(|x + 1| = a\), you need to consider both possible cases:
Remember these important points:
When dealing with an absolute value equation such as \(|x + 1| = a\), you need to consider both possible cases:
- Case 1: \(x + 1 = a\)
- Case 2: \(x + 1 = -a\)
Remember these important points:
- The expressions within the absolute value should be isolated first before attempting to solve the equation.
- Check whether the absolute value expression is set equal to a negative number, as this usually implies no solution exists.
Understanding Algebra
Algebra often forms the foundation for solving mathematical equations and can help you express real-world situations using mathematical expressions. When working with absolute value equations, algebra is the tool that allows us to manipulate expressions to isolate terms efficiently.
Let's explore key components of managing algebraic equations:
Let's explore key components of managing algebraic equations:
- Transform equations through addition, subtraction, multiplication, and division.
- Keep equations balanced by performing the same operation on both sides. This maintains equality.
- Use distributive properties and simplifications to make equations simpler to solve.
Isolating Terms
The objective of isolating terms in equations is to simplify them step-by-step until the unknown variable is clearly identified. This technique is key in both basic algebra and more complex calculus problems. Here’s why isolating terms is important:
To isolate terms efficiently, follow these strategies:
In our example of isolating \(3|x+1|-2=-11\), adding \(2\) to both sides and then dividing by \(3\) helped isolate the term \(|x+1|\). Recognizing when terms have been fully isolated is crucial, especially when dealing with absolute values, as it helps identify infeasible solutions early on.
- It systematically breaks down the equation, making it easier to manage.
- Ensures you can clearly see the relationship between variables.
- Facilitates the process of evaluating whether solutions are possible, as seen in our case with absolute values.
To isolate terms efficiently, follow these strategies:
- Perform inverse operations to both sides of the equation.
- Simplify algebraic expressions at each step to make subsequent steps easier.
- Rearrange terms logically to focus on the variable of interest.
In our example of isolating \(3|x+1|-2=-11\), adding \(2\) to both sides and then dividing by \(3\) helped isolate the term \(|x+1|\). Recognizing when terms have been fully isolated is crucial, especially when dealing with absolute values, as it helps identify infeasible solutions early on.
Other exercises in this chapter
Problem 5
Solve the equation. $$4(2 y+5)=3(5 y-2)$$
View solution Problem 5
Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ x^{2}-x-6
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Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$ (3+5 i)(2-7 i) $$
View solution Problem 5
Exer. 1-14: Solve the equation by factoring. $$ 2 x(4 x+15)=27 $$
View solution