Problem 5
Question
Estimate using the change of base formula. $$\log _{5} 6$$
Step-by-Step Solution
Verified Answer
\(\log_5 6 \approx 1.113\) using base 10.
1Step 1: State Change of Base Formula
The change of base formula allows us to convert logarithms with any given base to logarithms with another base (usually 10 or e). The formula is:\[ \log_a b = \frac{\log_c b}{\log_c a} \]where \(a\) is the original base, \(b\) is the argument of the logarithm, and \(c\) is the new base.
2Step 2: Choose New Base
Common choices for the new base \(c\) are \(10\) (common logarithm) or \(e\) (natural logarithm). In this exercise, we will use \(c = 10\).
3Step 3: Apply the Change of Base Formula
We apply the change of base formula to convert \(\log_5 6\):\[\log_5 6 = \frac{\log_{10} 6}{\log_{10} 5}\]This formula will allow us to use a calculator to find the approximate value of \(\log_5 6\).
4Step 4: Use a Calculator to Find Logs
Using a calculator, compute:- \(\log_{10} 6 \approx 0.7782\)- \(\log_{10} 5 \approx 0.6990\)
5Step 5: Divide the Logarithms
Now, divide the logarithms obtained in Step 4:\[\frac{\log_{10} 6}{\log_{10} 5} = \frac{0.7782}{0.6990} \approx 1.113\]Thus, \(\log_5 6 \approx 1.113\).
Key Concepts
LogarithmsCommon LogarithmNatural Logarithm
Logarithms
Logarithms are the inverse operation of exponentiation, much like how subtraction is the inverse of addition. They can help you figure out what power you need to raise a base number to, in order to get another number. For example, if you know that
- \( 2^3 = 8 \)
- Product Rule: \( \log_b (mn) = \log_b m + \log_b n \)
- Quotient Rule: \( \log_b \left( \frac{m}{n} \right) = \log_b m - \log_b n \)
- Power Rule: \( \log_b (m^n) = n \cdot \log_b m \)
Common Logarithm
A common logarithm has a base of 10 and is denoted as \( \log_{10} \). However, it's often just written as \( \log \) without the base shown. This is because using 10 as a base is so common, especially in scientific and technical fields.When you see \( \log \), you can assume it’s a base 10 logarithm, known for its utility with decimal and scientific notation:
- Common logarithms are particularly convenient for solving equations involving powers of 10.
- They are integrated into many calculators, making it easy to carry out calculations quickly.
- One practical use is in determining the pH of solutions, with the formula \( \text{pH} = -\log [H^+] \), where \([H^+]\) is the concentration of hydrogen ions.
Natural Logarithm
The natural logarithm is another special type of logarithm, and it has the base \( e \), an irrational constant approximately equal to 2.718. The natural logarithm is denoted as \( \ln \). Natural logarithms are used extensively in higher-level mathematics and calculus. Some reasons for their importance include:
- Growth and Decay Models: Natural logarithms are useful for modeling exponential growth and decay processes, such as population growth or radioactive decay.
- Calculus: Natural logarithms are linked with the derivative and integral of exponential functions. The function \( e^x \) has a derivative of \( e^x \), and its integral is \( \ln(x) \), showcasing the intertwined nature of \( e \) and logarithms.
- Finance: Compound interest calculations often involve \( e \), since \( e \) represents continuously compounded interest.
Other exercises in this chapter
Problem 5
Solve for \(t\) using logarithms with base \(a\). $$2 a^{2 / 3}=5$$
View solution Problem 5
Exer. 1-8: Express in terms of logarithms of \(x, y, z,\) or \(w\) $$\log \frac{\sqrt[3]{z}}{x \sqrt{y}}$$
View solution Problem 5
Determine whether the function \(f\) is one-to-one. $$f(x)=3 x-7$$
View solution Problem 5
Solve the equation. $$2^{-100 x}=(0.5)^{x-4}$$
View solution