Problem 5
Question
Draw the preferred conformation of each of the following: a. isopropylcyclohexane b. cyclohexylcyclohexane
Step-by-Step Solution
Verified Answer
Both compounds prefer conformations where bulky groups are equatorial, minimizing steric strain.
1Step 1: Identify the Cyclohexane Chair Conformation
Cyclohexane often exists in a chair conformation, which is the most stable due to minimized steric strain. Begin by drawing the chair conformation of cyclohexane.
2Step 2: Determine the Position of Substituents
For isopropylcyclohexane (part a), the isopropyl group is attached to a cyclohexane ring. Place the isopropyl group on an equatorial position to minimize steric hindrance. For cyclohexylcyclohexane (part b), treat one cyclohexane ring as a substituent on another. Again, position this cyclohexyl group equatorially on the main cyclohexane ring.
3Step 3: Draw the Complete Structures
Draw the full chair conformation for each compound by showing each cyclohexane ring and their respective equatorial substituents. Show the isopropyl group properly branching in the case of isopropylcyclohexane, and for cyclohexylcyclohexane, accurately depict the connected cyclohexane rings.
4Step 4: Verify the Drawings for Stability
Ensure that both isopropyl and cyclohexyl groups are at equatorial positions in your drawings. This reduces 1,3-diaxial interactions, making the conformations more stable.
Key Concepts
CyclohexaneSteric HindranceEquatorial Position1,3-Diaxial Interactions
Cyclohexane
Cyclohexane is a fascinating organic compound. It usually exists in a chair conformation, making it especially stable. This stability comes from minimized steric strain. Steric strain occurs when atoms are too close to each other, causing repulsion. The chair conformation of cyclohexane avoids this by having staggered bonds.
- It resembles a relaxed structure similar to a chair, hence its name.
- This conformation allows for optimal spatial arrangement of hydrogen atoms, keeping them apart.
- The result is a more energetically favorable and less strained configuration.
Steric Hindrance
Steric hindrance is a crucial concept when dealing with molecules like cyclohexane. It occurs when atoms or groups of atoms crowd each other, which can impact the molecule's reactivity and stability. In the case of cyclohexane, substitution positions, such as axial or equatorial, can significantly affect steric hindrance.
- Axial positions are parallel to the vertical axis of the ring, often resulting in higher steric hindrance.
- Equatorial positions extend outward around the plane of the ring, allowing for more space and reducing hindrance.
Equatorial Position
The equatorial position in a chair conformation is key for reducing steric hindrance. In a cyclohexane ring, substituents can be placed either axially or equatorially. The equatorial position is preferable for larger substituents as it offers more room, minimizing collisions and interactions.
- Equatorial positions lie along the "equator" of the cyclic structure, spreading outwards.
- This position allows larger groups like isopropyl or cyclohexyl to accommodate without causing strain.
- It's the ideal placement for optimizing stability and minimizing 1,3-diaxial interactions.
1,3-Diaxial Interactions
1,3-Diaxial interactions are specific kinds of steric hindrance that occur in cyclohexane. These interactions happen between axial hydrogen atoms and bulky groups at 1,3 positions on the ring.
- They can cause destabilization due to increased repulsion.
- Larger groups in axial positions are likelier to encounter these interactions.
Other exercises in this chapter
Problem 1
Write expanded structures showing the \(C-C\) bonds for each of the following condensed formulas. Name each substance by the IUPAC system. a. \(\left(\mathrm{CH
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Using the sawhorse convention, draw the possible conformations of chlorocyclohexane with the ring carbons in the planar, in the chair, and in the extreme boat f
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Draw the possible chair conformations of trans- and cis-1,3-dimethylcyclohexane. Is the cis or the trans isomer more likely to be the more stable? Explain.
View solution Problem 18
Investigate the thermodynamic feasibility of the following propagation steps for opening the rings of cycloalkanes with \(n=2\) to \(n=6\) by a radical-chain me
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