Problem 5
Question
Determine if \(B\) is the inverse matrix of \(A\) by calculating \(A B\) and \(B A\) $$ A=\left[\begin{array}{rrr} 2 & 1 & -1 \\ 3 & 0 & 2 \\ -1 & 0 & 1 \end{array}\right], \quad B=\left[\begin{array}{rrr} 0 & 1 & -2 \\ 1 & -3 & 7 \\ 0 & -1 & 3 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
Yes, \(B\) is the inverse of \(A\) because \(AB = I\) and \(BA = I\).
1Step 1: Define the Operations
To determine if matrix \(B\) is the inverse of matrix \(A\), we need to calculate the product \(AB\) and \(BA\). If both products result in the identity matrix, then \(B\) is the inverse of \(A\). The identity matrix for a 3x3 matrix is \(I = \left[\begin{array}{rrr}1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1\end{array}\right]\).
2Step 2: Compute Matrix Product \(AB\)
Calculate the product \(AB\) by multiplying matrix \(A\) by matrix \(B\):\(AB = \begin{bmatrix}2 & 1 & -1 \ 3 & 0 & 2 \ -1 & 0 & 1\end{bmatrix} \cdot \begin{bmatrix}0 & 1 & -2 \ 1 & -3 & 7 \ 0 & -1 & 3\end{bmatrix} = \begin{bmatrix}(2\cdot0 + 1\cdot1 + -1\cdot0) & (2\cdot1 + 1\cdot-3 + -1\cdot-1) & (2\cdot-2 + 1\cdot7 + -1\cdot3) \ (3\cdot0 + 0\cdot1 + 2\cdot0) & (3\cdot1 + 0\cdot-3 + 2\cdot-1) & (3\cdot-2 + 0\cdot7 + 2\cdot3) \ (-1\cdot0 + 0\cdot1 + 1\cdot0) & (-1\cdot1 + 0\cdot-3 + 1\cdot-1) & (-1\cdot-2 + 0\cdot7 + 1\cdot3)\end{bmatrix} \)Simplifying each entry, we get:\(AB = \begin{bmatrix}1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1\end{bmatrix} = I\)
3Step 3: Compute Matrix Product \(BA\)
Calculate the product \(BA\) by multiplying matrix \(B\) by matrix \(A\):\(BA = \begin{bmatrix}0 & 1 & -2 \ 1 & -3 & 7 \ 0 & -1 & 3\end{bmatrix} \cdot \begin{bmatrix}2 & 1 & -1 \ 3 & 0 & 2 \ -1 & 0 & 1\end{bmatrix} \)Continue with the multiplication:\(= \begin{bmatrix}(0\cdot2 + 1\cdot3 + -2\cdot-1) & (0\cdot1 + 1\cdot0 + -2\cdot0) & (0\cdot-1 + 1\cdot2 + -2\cdot1) \ (1\cdot2 + -3\cdot3 + 7\cdot-1) & (1\cdot1 + -3\cdot0 + 7\cdot0) & (1\cdot-1 + -3\cdot2 + 7\cdot1) \ (0\cdot2 + -1\cdot3 + 3\cdot-1) & (0\cdot1 + -1\cdot0 + 3\cdot0) & (0\cdot-1 + -1\cdot2 + 3\cdot1)\end{bmatrix} \)Simplifying each entry, we have:\(BA = \begin{bmatrix}1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1\end{bmatrix} = I\)
4Step 4: Conclusion: Confirm Inverse
Since both \(AB\) and \(BA\) equal the identity matrix \(I\), matrix \(B\) is indeed the inverse of matrix \(A\).
Key Concepts
Matrix MultiplicationIdentity MatrixMatrix Algebra
Matrix Multiplication
Matrix multiplication is a fundamental operation in matrix algebra. To multiply two matrices, the number of columns in the first matrix must match the number of rows in the second matrix. This ensures that each element in the resulting matrix is derived from the sum of products:
- The entry in the first row and first column is calculated by multiplying each element of the first row in the first matrix by the corresponding element in the first column of the second matrix and adding them up.
- This process is repeated for each element in the resulting matrix.
Identity Matrix
The identity matrix plays a critical role in matrix algebra, much like the number 1 does in basic arithmetic. For a matrix to have an inverse, there must exist an identity matrix such that when multiplied with its inverse, results in the identity matrix itself:
- An identity matrix is a square matrix with 1s on the diagonal and 0s elsewhere.
- For a 3x3 identity matrix, it's represented as \[\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}\]
Matrix Algebra
Matrix algebra amalgamates rules and operations that guide how matrices are used together. It encompasses operations like matrix addition, scalar multiplication, and the more complex operations of multiplication and finding inverses.
Key rules of matrix algebra include:
Key rules of matrix algebra include:
- Associative Rule: (AB)C = A(BC)
- Distributive Rule: A(B + C) = AB + AC
- Identity Element: For any matrix A, A multiplied by the identity matrix I results in A.
Other exercises in this chapter
Problem 5
Graph the solution set to the inequality. $$ x+y \leq 2 $$
View solution Problem 5
Find the specified minor and cofactor for \(A\). $$ M_{12} \text { and } A_{12} \text { if } A=\left[\begin{array}{rrr} 1 & -1 & 3 \\ 2 & 3 & -2 \\ 0 & 1 & 5 \e
View solution Problem 5
Represent the linear system by an augmented matrix, and state the dimension of the matrix. $$ \begin{aligned} -3 x+2 y+z &=-4 \\ 5 x &=9 \\ x-3 y-6 z &=-9 \end{
View solution Problem 5
Evaluate the expression for the given \(f(x, y)\). $$ f(-2,3) \text { if } f(x, y)=3 x-4 y $$
View solution