Problem 5
Question
1–8 Write a polar equation of a conic that has its focus at the origin and satisfies the given conditions. Hyperbola, eccentricity \(4,\) directrix \(r=5 \sec \theta\)
Step-by-Step Solution
Verified Answer
The polar equation of the hyperbola is \( r = \frac{20}{1 + 4 \cos \theta} \).
1Step 1: Understand the characteristics of a hyperbola
A hyperbola has an eccentricity greater than 1. Given that the eccentricity is 4, we know that we are dealing with a hyperbola since the eccentricity is greater than 1.
2Step 2: Write the polar form equation
The polar form of a conic section with eccentricity \( e \) and directrix \( d \) is \( r = \frac{ed}{1 + e\cos\theta} \) if the directrix is vertical or \( r = \frac{ed}{1 + e\sin\theta} \) if the directrix is horizontal.
3Step 3: Identify the type of directrix
The directrix given is \( r = 5 \sec\theta \), which is a vertical line. This suggests that \( \cos\theta \) is used in the equation.
4Step 4: Substitute the values into the polar form equation
Since the directrix \( r = 5 \sec\theta \) corresponds to \( x = 5 \) in Cartesian coordinates, the distance \( d \) from the origin to this line is 5. Substitute \( e = 4 \) and \( d = 5 \) into the polar equation: \[ r = \frac{4 \cdot 5}{1 + 4\cos\theta} \].
5Step 5: Simplify the equation
Simplify the equation: \[ r = \frac{20}{1 + 4 \cos \theta} \]. This is the equation of the hyperbola in polar coordinates with focus at the origin, eccentricity 4, and a vertical directrix.
Key Concepts
Polar EquationsHyperbolaEccentricity
Polar Equations
Polar equations are a way to represent curves using a coordinate system based on angles and distances from a fixed point. Unlike the Cartesian coordinate system, which uses x and y axes, polar coordinates describe the position of a point as
A conic section, such as an ellipse, parabola, or hyperbola, can be represented using a polar equation that depends on its eccentricity and directrix. The general polar form of a conic with its focus at the origin is written as:\[ r = \frac{ed}{1 + e \cos \theta} \] if the directrix is vertical, or as:\[ r = \frac{ed}{1 + e \sin \theta} \] if the directrix is horizontal.
This setup allows you to model conics like hyperbolas in a simple and intuitive way, making it easier to study their properties in polar coordinates.
- a distance ( ") from the origin (also known as the pole)
- an angle ( heta), measured from a reference direction
A conic section, such as an ellipse, parabola, or hyperbola, can be represented using a polar equation that depends on its eccentricity and directrix. The general polar form of a conic with its focus at the origin is written as:\[ r = \frac{ed}{1 + e \cos \theta} \] if the directrix is vertical, or as:\[ r = \frac{ed}{1 + e \sin \theta} \] if the directrix is horizontal.
This setup allows you to model conics like hyperbolas in a simple and intuitive way, making it easier to study their properties in polar coordinates.
Hyperbola
A hyperbola is one of the distinct types of conic sections formed when a plane cuts through a double cone. It has two separate curves, which may look like mirror images of each other.When represented in a polar coordinate system, it assumes a unique form. The equation of a hyperbola in polar form involves the eccentricity \( e \), which is greater than 1 for hyperbolas, and the directrix distance \( d \).Key features of a hyperbola include:
- Two distinct branches, each asymptotically approaching a pair of lines.
- An eccentricity \( e > 1 \).
- A focal length that extends to infinity, as the branches continue indefinitely.
Eccentricity
Eccentricity is a crucial parameter in defining the shape of a conic section. It determines how "stretched" or "flattened" the conic appears.Here's how eccentricity values classify different conic shapes:
Eccentricity measures how much the conic deviates from being circular. In a polar equation, eccentricity directly influences the curve’s equation form and its characteristics. For hyperbolas, larger eccentricity results in more spread-out branches. Understanding eccentricity helps not only in solving equations but also in visualizing the shapes and behaviors of the conic sections.
- If \( e = 0 \), the conic is a circle.
- If \( 0 < e < 1 \), the conic is an ellipse.
- If \( e = 1 \), the conic is a parabola.
- If \( e > 1 \), the conic is a hyperbola.
Eccentricity measures how much the conic deviates from being circular. In a polar equation, eccentricity directly influences the curve’s equation form and its characteristics. For hyperbolas, larger eccentricity results in more spread-out branches. Understanding eccentricity helps not only in solving equations but also in visualizing the shapes and behaviors of the conic sections.
Other exercises in this chapter
Problem 5
Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. $$ \frac{x^{2}}{25}+\frac{y^{
View solution Problem 5
Determine the \(X Y\) -coordinates of the given point if the coordinate axes are rotated through the indicated angle. $$(0,2), \quad \phi=55^{\circ}$$
View solution Problem 5
Find the vertex, focus, and directrix of the parabola, and sketch the graph. $$ (x-3)^{2}=8(y+1) $$
View solution Problem 5
Find the vertices, foci, and asymptotes of the hyperbola, and sketch its graph. \(\frac{x^{2}}{4}-\frac{y^{2}}{16}=1\)
View solution