Problem 49
Question
\(z^{2}-20 z+164=0\)
Step-by-Step Solution
Verified Answer
The solutions are \(z = 10 + 8i\) and \(z = 10 - 8i\).
1Step 1 - Identify coefficients
The given equation is a quadratic equation in the form of \(ax^2 + bx + c = 0\). Identify the coefficients: \(a = 1\), \(b = -20\), and \(c = 164\).
2Step 2 - Compute the discriminant
The discriminant \(\Delta\) of a quadratic equation \(ax^2 + bx + c = 0\) is given by \(\Delta = b^2 - 4ac\). Substitute the values to find the discriminant: \(\Delta = (-20)^2 - 4 \cdot 1 \cdot 164 = 400 - 656 = -256\).
3Step 3 - Analyze the discriminant
Since the discriminant \(\Delta = -256\) is less than zero, the quadratic equation has two complex solutions.
4Step 4 - Use the quadratic formula
The quadratic formula is given by \[z = \frac{-b \pm \sqrt{\Delta}}{2a}\]. Substituting the values, we get \[z = \frac{-(-20) \pm \sqrt{-256}}{2 \cdot 1}\].
5Step 5 - Simplify the expression
Simplify the expression under the square root and perform the division:\[z = \frac{20 \pm \sqrt{256i^2}}{2}\], where \(i\) is the imaginary unit. Therefore, \(\sqrt{-256} = 16i\).
6Step 6 - Calculate the roots
Continue simplifying to get the roots:\[z = \frac{20 \pm 16i}{2}\]\[z = 10 \pm 8i\].
Key Concepts
quadratic formuladiscriminantcomplex solutionsimaginary unit
quadratic formula
To solve quadratic equations, we often use the quadratic formula. This formula provides a way to find the roots of any quadratic equation of the form h4.
Let's breakdown the quadratic formula step by step:
Using the quadratic formula, we can solve the given equation
Using the quadratic formula, you can confidently solve any quadratic equation!
Let's breakdown the quadratic formula step by step:
- The term
- The fraction
- The part under the square root
Using the quadratic formula, we can solve the given equation
Using the quadratic formula, you can confidently solve any quadratic equation!
discriminant
The discriminant provides useful information about the nature of the roots. It is found inside the quadratic formula in the part under the square root sign. You calculate it using the formula
Let's go through this step-by-step:
This negative discriminant tells us that our solutions will be complex.
Let's go through this step-by-step:
- If the discriminant is positive, there are two distinct real solutions.
- If the discriminant is zero, there is exactly one real solution (also known as a repeated root).
- If the discriminant is negative, there are two complex solutions.
This negative discriminant tells us that our solutions will be complex.
complex solutions
When the discriminant is negative, our quadratic equation has complex solutions. Complex solutions come in conjugate pairs. They have the form
In practice, this means one solution will be
In our example, the complex solutions are
These numbers cannot be placed on the regular number line; instead, they can be shown on a complex plane where the horizontal axis represents the real part and the vertical axis represents the imaginary part.
In practice, this means one solution will be
In our example, the complex solutions are
These numbers cannot be placed on the regular number line; instead, they can be shown on a complex plane where the horizontal axis represents the real part and the vertical axis represents the imaginary part.
imaginary unit
The imaginary unit is denoted by
The idea behind the imaginary unit is to extend the real number system. Sometimes, we need to calculate the square root of a negative number.
To understand the imaginary unit better, remember these fundamental rules:
This use of the imaginary unit allowed us to find the complex solutions.
The idea behind the imaginary unit is to extend the real number system. Sometimes, we need to calculate the square root of a negative number.
To understand the imaginary unit better, remember these fundamental rules:
This use of the imaginary unit allowed us to find the complex solutions.
Other exercises in this chapter
Problem 48
\(m^{2}-18 m+78=0\)
View solution Problem 48
\(2 f^{2}+14=94\)
View solution Problem 49
The area of a rectangle is \(221 \mathrm{ft}^{2}\), and the perimeter is \(60 \mathrm{ft}\). Find the length and width of this rectangle.
View solution Problem 49
\(u^{2}+20 u-3=0\)
View solution