Problem 49
Question
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. For example, $$ \begin{aligned} \sqrt{-3} \sqrt{-8} &=(i \sqrt{3})(i \sqrt{8}) \\ &=i^{2} \sqrt{24} \\ &=(-1) \sqrt{4} \sqrt{6} \\ &=-2 \sqrt{6} \end{aligned} $$ $$\sqrt{-15} \sqrt{-5}$$
Step-by-Step Solution
Verified Answer
\(-5\sqrt{3}\)
1Step 1: Express in Terms of i
Start by expressing each square root in terms of the imaginary unit, \(i\). The imaginary unit is defined as \(i = \sqrt{-1}\). Therefore, \(\sqrt{-15} = i \sqrt{15}\) and \(\sqrt{-5} = i \sqrt{5}\).
2Step 2: Multiply the Expressions
Perform the multiplication of the two expressions we found in Step 1. Multiply \( (i \sqrt{15})(i \sqrt{5}) \).
3Step 3: Simplify Using i^2
Recognize that \( i^2 = -1 \). So, \( (i \sqrt{15})(i \sqrt{5}) = i^2 \sqrt{75} = -\sqrt{75} \).
4Step 4: Simplify the Square Root
Simplify \( \sqrt{75} \). Since \( 75 = 25 \times 3 \), we have \( \sqrt{75} = \sqrt{25 \times 3} = \sqrt{25} \sqrt{3} = 5 \sqrt{3} \).
5Step 5: Final Result
Combine the result from Steps 3 and 4 to express the final answer: \( -\sqrt{75} = -5\sqrt{3} \).
Key Concepts
Imaginary UnitSimplifying Square RootsMultiplying Complex Numbers
Imaginary Unit
When dealing with complex numbers, one of the most important concepts is the imaginary unit, denoted as \( i \). At its core, \( i \) is defined as \( \sqrt{-1} \).
This means that whenever you encounter a square root of a negative number, you can express it using \( i \).
This means that whenever you encounter a square root of a negative number, you can express it using \( i \).
- For example, \( \sqrt{-4} \) is expressed as \( 2i \) because it equals \( \sqrt{4} \cdot \sqrt{-1} = 2 \cdot i \).
- Similarly, \( \sqrt{-9} = 3i \).
Simplifying Square Roots
Simplifying square roots is crucial when working with any type of number, including complex numbers. The process involves breaking down a square root into its simplest form.
For a positive square root, like \( \sqrt{75} \), we find factors that are perfect squares.
For a positive square root, like \( \sqrt{75} \), we find factors that are perfect squares.
- Identify that 75 can be factored into 25 and 3, with 25 being a perfect square.
- This means \( \sqrt{75} = \sqrt{25 \times 3} \), which simplifies to \( 5\sqrt{3} \).
Multiplying Complex Numbers
Multiplying complex numbers involves not only multiplying their real and imaginary parts but also applying the fundamental identity \( i^2 = -1 \).
For instance, when multiplying two complex numbers (e.g., \((i \sqrt{15})(i \sqrt{5}) \)), follow these steps:
For instance, when multiplying two complex numbers (e.g., \((i \sqrt{15})(i \sqrt{5}) \)), follow these steps:
- Multiply the coefficients and the transitive \( i \)'s: \( i \cdot i = i^2 \), which equals \(-1\).
- This results in \( i^2 \sqrt{75} = -\sqrt{75} \).
Other exercises in this chapter
Problem 49
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$-6 x^{2}+2 x+1=0$$
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Solve each quadratic equation using the method that seems most appropriate. $$3 n^{2}-6 n+4=0$$
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Solve each inequality. $$\frac{x+2}{x+4} \leq 3$$
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Set up an equation and solve each problem. The length of a rectangular floor is 1 meter less than twice its width. If a diagonal of the rectangle is 17 meters,
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