Problem 49
Question
What volume of \(0.0962 \mathrm{M} \mathrm{NaOH}\) is required to exactly neutralize \(10.00 \mathrm{mL}\) of \(0.128 \mathrm{M} \mathrm{HCl} ?\)
Step-by-Step Solution
Verified Answer
The required volume of \(0.0962 \, \mathrm{M} \, \mathrm{NaOH}\) needed to neutralize \(10.00 \, \mathrm{ml}\) of \(0.128 \, \mathrm{M} \, \mathrm{HCl}\) is \(13.3 \, \mathrm{ml}\).
1Step 1: Determine the Amount of Moles of HCl
Calculate the moles of HCl using its volume and molarity. The molarity (\(M\)) could be defined as moles of solute per litre of solution (\(M=n/V\)). Therefore, to calculate the number of moles (\(n\)), we multiply the volume (\(V = 10.00 \, \mathrm{ml}\)) by its molarity (\(M = 0.128 \, \mathrm{M}\)). We convert the volume from ml to L (since molarity is in terms of L) by dividing by 1000. Then we solve, \(n=(10.00/1000) \times 0.128 = 0.00128 \, \mathrm{moles}\) of HCl.
2Step 2: Use Stoichiometry of the Balanced Equation
According to the balanced equation for the reaction, one mole of HCl reacts with one mole of NaOH. Consequently, the number of moles of NaOH required for neutralization equals the number of moles of HCl, which is \(0.00128 \, \mathrm{moles}\).
3Step 3: Compute the Volume of NaOH Needed
Now the calculated moles of NaOH can be used to find the volume needed by using rearranged molarity formula: \(V=n/M\). Here, \(n=0.00128 \, \mathrm{moles}\) and \(M=0.0962 \, \mathrm{M}\). After calculating, we find that \(V=0.00128/0.0962 = 0.0133 \, \mathrm{L} = 13.3 \, \mathrm{ml}\).
Key Concepts
MolarityNeutralizationChemical Reactions
Molarity
Molarity is a fundamental concept in chemistry that refers to the concentration of a solute in a solution. It is expressed as moles of solute per litre of solution. Mathematically, it is given by the formula:
To convert between mL and L, divide the volume in mL by 1000, because there are 1000 ml in a litre. This is particularly important when using the molarity formula, as the volume must be in litres to match the unit of molarity. Understanding molarity is essential for performing accurate chemical calculations and preparing solutions properly.
- \[ M = \frac{n}{V} \]
To convert between mL and L, divide the volume in mL by 1000, because there are 1000 ml in a litre. This is particularly important when using the molarity formula, as the volume must be in litres to match the unit of molarity. Understanding molarity is essential for performing accurate chemical calculations and preparing solutions properly.
Neutralization
Neutralization is a chemical reaction where an acid and a base react to form a salt and water. This reaction is important in many everyday chemical processes, including antacid tablets reacting in the stomach to neutralize excess acid.
In a neutralization reaction, the acid donates H+ ions while the base donates OH- ions. These ions combine to form water, a process generally described by the equation:
In a neutralization reaction, the acid donates H+ ions while the base donates OH- ions. These ions combine to form water, a process generally described by the equation:
- \[ \text{H}^{+} + \text{OH}^{-} \rightarrow \text{H}_2\text{O} \]
- \[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \]
Chemical Reactions
Chemical reactions involve the transformation of reactants into products, and they are governed by specific stoichiometric ratios defined by balanced chemical equations. Understanding the concepts of reactants and products, along with how substances interact, is fundamental in chemistry.
When working with chemical reactions, it is important to observe the conservation of mass, indicating that the total mass of reactants equals the total mass of products. Equations must be balanced to reflect this.
There are various types of chemical reactions, but in the context of neutralization, acid-base reactions are key. These reactions often produce a salt and water, as exemplified by the reaction of HCl with NaOH. Balancing these equations requires knowing the exact quantities of substances that react, which can be determined using stoichiometry, allowing for precise calculations in chemistry labs and industrial processes alike. By mastering chemical reactions, you can predict outcomes in chemical experiments and understand the core principles of matter interaction.
When working with chemical reactions, it is important to observe the conservation of mass, indicating that the total mass of reactants equals the total mass of products. Equations must be balanced to reflect this.
There are various types of chemical reactions, but in the context of neutralization, acid-base reactions are key. These reactions often produce a salt and water, as exemplified by the reaction of HCl with NaOH. Balancing these equations requires knowing the exact quantities of substances that react, which can be determined using stoichiometry, allowing for precise calculations in chemistry labs and industrial processes alike. By mastering chemical reactions, you can predict outcomes in chemical experiments and understand the core principles of matter interaction.
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