Problem 49
Question
What is the final pressure of 1.00 mol of ammonia gas, initially at 1.00 atm, if the volume is a. gradually decreased from \(78.0 \mathrm{mL}\) to \(39.0 \mathrm{mL}\) at constant temperature? b. increased from \(43.5 \mathrm{mL}\) to \(65.5 \mathrm{mL}\) at constant temperature? c. decreased by \(40 \%\) at constant temperature?
Step-by-Step Solution
Verified Answer
Question: Calculate the final pressure of 1.00 mol of ammonia gas for each of the following scenarios, assuming a constant temperature: (a) the volume is decreased to half of its initial value, (b) the volume is increased from 43.5 mL to 65.5 mL, and (c) the volume is decreased by 40%.
Answer: (a) The final pressure in scenario (a) is 2.00 atm. (b) The final pressure in scenario (b) is approximately 0.666 atm. (c) The final pressure in scenario (c) is approximately 1.67 atm.
1Step 1: Write down Boyle's Law formula
Write down Boyle's Law formula, which is P1 * V1 = P2 * V2. This will help us calculate the final pressure (P2) for each scenario.
2Step 2: Calculate final pressure for scenario (a) decreasing the volume
Given the initial pressure P1 (1.00 atm), initial volume V1 (78.0 mL) and final volume V2 (39.0 mL), plug the values into the formula:
P2 = (P1 * V1) / V2
P2 = (1.00 atm * 78.0 mL) / 39.0 mL
P2 = 2.00 atm
The final pressure in scenario (a) is 2.00 atm.
3Step 3: Calculate final pressure for scenario (b) increasing the volume
Given the initial pressure P1 (1.00 atm), initial volume V1 (43.5 mL) and final volume V2 (65.5 mL), plug the values into the formula:
P2 = (P1 * V1) / V2
P2 = (1.00 atm * 43.5 mL) / 65.5 mL
P2 ≈ 0.666 atm
The final pressure in scenario (b) is approximately 0.666 atm.
4Step 4: Calculate final pressure for scenario (c) decreasing the volume by a percent
First, you need to find the final volume after a 40% decrease. We don't have the value for V1 in this case, so let's assume V1 = x mL. The final volume V2 will be 0.6 * V1 (since it's being decreased by 40%).
Now, use the Boyle's Law formula:
P2 = (P1 * V1) / V2
P2 = (1.00 atm * x mL) / (0.6x mL)
After canceling out the x terms:
P2 = 1.00 atm / 0.6
P2 ≈ 1.67 atm
The final pressure in scenario (c) is approximately 1.67 atm.
Key Concepts
Gas Pressure CalculationsVolume Change in GasesAmmonia Gas Properties
Gas Pressure Calculations
Gas pressure calculations often rely on understanding Boyle's Law. This principle states that for a given amount of gas at constant temperature, the product of its pressure and volume is constant. Hence, if you know the initial pressure and volume, you can find the final pressure when the volume changes, as per the relation: \[ P_1 \times V_1 = P_2 \times V_2 \] Here, \(P_1\) and \(V_1\) represent the initial pressure and volume, while \(P_2\) and \(V_2\) are the final pressure and volume, respectively. Using Boyle's Law allows us to calculate how changing the volume of a gas influences its pressure—provided the temperature does not vary. This relationship is inversely proportional, meaning if the volume decreases, the pressure increases, and vice versa. To solve practical problems:
- Identify initial conditions: initial pressure and volume.
- Determine the new volume condition.
- Use the formula above to solve for the unknown pressure.
Volume Change in Gases
Volume changes in gases are pivotal in many scientific and industrial applications. By compressing or expanding a gas, we can significantly alter its properties and behavior. Boyle's Law is central to understanding these changes. It tells us that when the volume of a gas decreases, its pressure increases, assuming the temperature and the amount of gas remain constant.
For example:
- If a gas's volume is halved, its pressure doubles.
- If the volume increases, the pressure drops.
Ammonia Gas Properties
Ammonia is a colorless gas with a distinctive pungent smell. It is composed of nitrogen and hydrogen, having the chemical formula \(\text{NH}_3\). Its properties make it suitable for numerous applications, ranging from fertilizers to industrial refrigerants. Key characteristics of ammonia include:
- Light molecular weight, making it suitable for uses such as a cleansing agent.
- Ability to be easily compressed, which facilitates its storage and transport.
- High solubility in water, leading to its widespread use in aqueous solutions for cleaning and sanitation.
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