Problem 49
Question
Vertex \((-9,1)\), symmetric with respect to the line \(x=-9\), and contains the point \((-8,0)\) $$ x^{2}+18 x+y+80=0 $$
Step-by-Step Solution
Verified Answer
The parabola's vertex is (-9,1) and it includes the point (-8,0), verifying all given conditions.
1Step 1: Identify the form of the parabola equation
The given equation of the parabola is \(x^2+18x+y+80=0\). To identify its form, rewrite it as \(y = -x^2 - 18x - 80\), which shows that the parabola opens downwards since the coefficient of \(x^2\) is negative.
2Step 2: Verify the vertex
The standard form of a parabola is \(y = ax^2 + bx + c\). The vertex \((h, k)\) of a parabola \(y = ax^2 + bx + c\) can be found using the formula \((h, k) = (-\frac{b}{2a}, f(h))\). Using the given function, \(a = -1\) and \(b = -18\), the vertex is \(h = -\frac{-18}{2(-1)} = -9\). Evaluate \(f(-9)\) to find \(k\): \(y = -(-9)^2 - 18(-9) - 80 = 1\). Thus, the vertex is correct at \((-9, 1)\).
3Step 3: Confirm symmetry
A parabola that is symmetric with respect to a vertical line will have this line as its axis of symmetry. Since the axis of symmetry is \(x = -9\), which passes through the vertex \((-9,1)\), it confirms symmetry as an expected property given the vertex.
4Step 4: Check if the point \((-8,0)\) lies on the parabola
Substitute \((-8,0)\) into the equation to verify if it satisfies it: \(-(8)^2 - 18(-8) - 80 = 0\). Calculate: \(-64 + 144 - 80 = 0\). Since this equation holds, the point \((-8,0)\) lies on the parabola.
Key Concepts
Vertex FormAxis of SymmetryQuadratic Equation
Vertex Form
The vertex form of a parabola makes it easy to identify the vertex coordinates of the function. Vertex form is written as \( y = a(x-h)^2 + k \), where \( (h, k) \) represents the vertex point of the parabola. This format is especially useful because it tells us at a glance the highest or lowest point on the parabola, known as the vertex.
In this exercise, the original quadratic was in the form \( y = -x^2 - 18x - 80 \). By transforming this into something resembling the vertex formula, we identify the vertex at \((-9, 1)\).
Reasons it's beneficial for a student to understand:
In this exercise, the original quadratic was in the form \( y = -x^2 - 18x - 80 \). By transforming this into something resembling the vertex formula, we identify the vertex at \((-9, 1)\).
Reasons it's beneficial for a student to understand:
- Quickly find the vertex, which is crucial for graphing.
- Understand shifts and transformations of parabolas.
Axis of Symmetry
The axis of symmetry in a parabola is a vertical line that divides the parabola into two mirror images. This line passes through the vertex of the parabola. Its equation is always in the form \(x = h\), where \(h\) is the x-coordinate of the vertex.
For the given function, we calculated that \(h = -9\). Thus, the axis of symmetry is \(x = -9\).
Importance of the axis of symmetry includes:
For the given function, we calculated that \(h = -9\). Thus, the axis of symmetry is \(x = -9\).
Importance of the axis of symmetry includes:
- It helps confirm the vertex location.
- It aids in graphing the parabola accurately.
Quadratic Equation
Quadratic equations form the basis for understanding parabolas. A quadratic equation is any polynomial equation of the form \( ax^2 + bx + c = 0 \). When graphed, these equations create a shape called a parabola.
Our exercise featured the quadratic \(-x^2 - 18x - 80 = 0\). By graphing or analyzing this equation, you can tell that it represents a downward opening parabola due to the negative coefficient of \(x^2\).
The squared term, \( x^2 \), dictates that the curve will be symmetric. Understanding quadratics is vital because:
Our exercise featured the quadratic \(-x^2 - 18x - 80 = 0\). By graphing or analyzing this equation, you can tell that it represents a downward opening parabola due to the negative coefficient of \(x^2\).
The squared term, \( x^2 \), dictates that the curve will be symmetric. Understanding quadratics is vital because:
- They model many real-world scenarios.
- They set the stage for more complex algebraic concepts.
Other exercises in this chapter
Problem 46
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