Problem 49
Question
Use the formula \(A=P e^{r t}\) to solve. How much money does Barbara Mack owe at the end of 4 years if \(6 \%\) interest is compounded continuously on her \(\$ 2000\) debt?
Step-by-Step Solution
Verified Answer
Barbara Mack owes approximately $2542.50 at the end of 4 years.
1Step 1: Identify Given Variables
The variables in the formula \(A=Pe^{rt}\) are as follows: \(P\) is the principal amount, \(r\) is the rate of interest, and \(t\) is the time period. From the question, we identify \(P = 2000\), \(r = 0.06\), and \(t = 4\).
2Step 2: Substitute Values into Formula
Substitute the identified values into the formula: \[A = 2000 \times e^{0.06 \times 4}\].
3Step 3: Calculate the Exponent
First, calculate the exponent: \(0.06 \times 4 = 0.24\). Thus, the formula becomes \[A = 2000 \times e^{0.24}\].
4Step 4: Evaluate the Exponential Component
Calculate \(e^{0.24}\) using a calculator. This results in approximately \(1.27125\).
5Step 5: Calculate the Final Amount
Multiply the result by the principal \(P\): \[A = 2000 \times 1.27125 = 2542.50\].
Key Concepts
Exponential FunctionsContinuous CompoundingInterest CalculationAlgebraic Formulas
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. They are characterized by a constant rate of growth or decay. This constant base is often represented by the mathematical constant \(e\), which is approximately equal to 2.71828. In finance and other contexts, \(e\) comes into play in continuous growth scenarios such as compounding interests.
Understanding exponential functions is crucial because they model various growth patterns in real-life situations, such as population growth, radioactive decay, and investment growth through compound interest.
When utilizing exponential functions, remember that the rate at which the function increases is proportional to its current value, which gives them their unique runaway effect.
Understanding exponential functions is crucial because they model various growth patterns in real-life situations, such as population growth, radioactive decay, and investment growth through compound interest.
When utilizing exponential functions, remember that the rate at which the function increases is proportional to its current value, which gives them their unique runaway effect.
Continuous Compounding
Continuous compounding refers to the mathematical idea where interest is calculated and added to the principal continuously, allowing interest to be accrued at every possible moment. Unlike traditional compounding, which might occur annually, semi-annually, or quarterly, continuous compounding uses the power of exponential functions to determine how the principal grows over time.
The formula for continuous compounding is typically given by \(A = Pe^{rt}\), where:
The formula for continuous compounding is typically given by \(A = Pe^{rt}\), where:
- \(A\) is the final amount.
- \(P\) is the initial principal balance.
- \(r\) is the annual interest rate.
- \(t\) is the time in years.
Interest Calculation
Interest calculation, especially when compounded continuously, is crucial in understanding how an investment grows over time. To calculate the future value of an investment with continuous compounding, we use the formula \(A = Pe^{rt}\).
Here's how you apply it:
Here's how you apply it:
- Start with the initial amount (principal \(P\)) you want to invest.
- Multiply the annual interest rate \(r\) (expressed as a decimal) by the time \(t\) the money is invested.
- Raise \(e\), the base of natural logarithms, to this product.
- Finally, multiply the result by your principal \(P\) to find the accumulated amount \(A\).
Algebraic Formulas
Algebraic formulas like \(A = Pe^{rt}\) serve as vital tools in solving compound interest problems. With a solid grasp of algebra, you can manipulate and solve these formulas to find unknown variables.
Here’s a breakdown of how the formula components work:
Here’s a breakdown of how the formula components work:
- \(A\) is the desired end value or the amount you want to calculate.
- \(P\) refers to the principal you initially invest.
- \(e\) is the mathematical constant for the natural exponential function.
- \(r\) is the interest rate, always expressed as a decimal.
- \(t\) signifies the time in years.
Other exercises in this chapter
Problem 49
Psychologists call the graph of the formula \(t=\frac{1}{c} \ln \left(\frac{A}{A-N}\right)\) the learning curve since the formula relates time t passed, in week
View solution Problem 49
Solve. $$ \log _{x} 49=2 $$
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If \(f(x)=3^{x}\), find each value. give an exact answer and a two-decimal-place approximation. See Sections 8.2 and \(10.2 .\) $$ f(2) $$
View solution Problem 49
Write each expression as a sum or difference of logarithms. Assume that variables represent positive numbers. $$ \log _{5} x^{3}(x+1) $$
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