Problem 49
Question
Use synthetic substitution to determine whether the given number is a zero of the polynomial. $$-0.5 ; \quad P(x)=4 x^{3}+12 x^{2}+7 x+1$$
Step-by-Step Solution
Verified Answer
Yes, -0.5 is a zero of the polynomial.
1Step 1: Set Up Synthetic Substitution
To use synthetic substitution, we first need to set up our synthetic division table. The coefficients of the polynomial \( P(x) = 4x^3 + 12x^2 + 7x + 1 \) are \( 4, 12, 7, 1 \). We will use \( -0.5 \) as the divisor.
2Step 2: Perform Synthetic Division
Write the coefficients \( 4, 12, 7, 1 \) in a row. Bring down the first coefficient, \( 4 \), as is. Then multiply \( 4 \) by \(-0.5\) to get \(-2\), and add this to the next coefficient \( 12 \) to get \( 10 \). Repeat the process for all coefficients:1. Multiply \( 10 \) by \(-0.5\) to get \(-5\), add to \( 7 \) to get \( 2 \).2. Multiply \( 2 \) by \(-0.5\) to get \(-1\), add to \( 1 \) to get \( 0 \).The final row of numbers should be \( 4, 10, 2, 0 \).
3Step 3: Determine the Remainder
The last number \( 0 \) from the synthetic division represents the remainder of the polynomial when divided by \( x + 0.5 \) (since \(-0.5\) would create a factor of \( x + 0.5 \)). If the remainder is \( 0 \), then \(-0.5\) is a zero of the polynomial.
4Step 4: Conclude Whether the Number is a Zero
Since the remainder is \( 0 \), it means that \(-0.5\) is indeed a zero of the polynomial \( P(x) = 4x^3 + 12x^2 + 7x + 1 \).
Key Concepts
PolynomialsZeros of PolynomialsSynthetic Division
Polynomials
Polynomials are expressions comprised of variables and coefficients, combined using addition, subtraction, multiplication, and exponentiation with non-negative integer exponents. They are fundamental in algebra and appear in many forms such as quadratics, cubics, quartics, and more. To illustrate, a simple polynomial is given as:
- A linear polynomial: \( P(x) = ax + b \)
- A quadratic polynomial: \( P(x) = ax^2 + bx + c \)
- A cubic polynomial: \( P(x) = ax^3 + bx^2 + cx + d \)
Zeros of Polynomials
Zeros or roots of a polynomial are the values of the variable which make the polynomial equal to zero. In simpler terms, these are the solutions to the polynomial equation \( P(x) = 0 \). Zeros can be real or complex numbers and are fundamental in graphing polynomials, as they tell us where the graph intersects the x-axis. To find if a particular number is a zero of a given polynomial, such as \(-0.5\) in our exercise, we substitute it into the polynomial and simplify. If the result is zero, the number is a zero of the polynomial.For example, suppose \( 3 \) is a zero of the polynomial \( P(x) = x^2 - 5x + 6 \). Substituting \( 3 \) will yield \( P(3) = 3^2 - 5 \, \cdot \, 3 + 6 = 0 \). Thus, 3 is indeed a zero. Finding zeros is a significant task because they provide information about the polynomial's factorization and graph behavior.
Synthetic Division
Synthetic Division is a simplified method of dividing a polynomial by a binomial of the form \( x - c \). It is particularly useful for finding zeros and quickly evaluating polynomials. The process reduces the complexity of traditional long division and makes calculations more straightforward.Here's a step-by-step breakdown of synthetic division as used in our example:
- Set up the synthetic division: Write down the coefficients of the polynomial. Also, write the constant \(-c\) which is derived from the divisor \(x - c\).
- Perform calculations: Start with the leading coefficient, bring it down unchanged. Multiply it by \(-c\) and add it to the next coefficient, continuing the process to the end.
- Analyze the result: The last number in the row represents the remainder. If the remainder is zero, the divisor is indeed a factor, making \( c \) a zero of the polynomial.
Other exercises in this chapter
Problem 48
Use synthetic substitution to determine whether the given number is a zero of the polynomial. $$-4 ; \quad P(x)=9 x^{3}+39 x^{2}+12 x$$
View solution Problem 48
Solve each equation and inequality, where \(k\) is a positive constant. (a) \(4 x^{3}-k x=0\) (b) \(4 x^{3}-k x>0\)
View solution Problem 49
Use the concepts of this section to answer the following. What are the possible numbers of real zeros (counting multiplicities) for a polynomial function with r
View solution Problem 49
Use a graphical method to find all real solutions of each equation. Express solutions to the nearest hundredth. $$0.86 x^{3}-5.24 x^{2}+3.55 x+7.84=0$$
View solution