Problem 49
Question
The system of equations \(2 x-3 y+6 z-5 t=3, y-4 z+\) \(t=1,4 x-5 y+8 z-9 t=k\) has (A) no solution if \(k \neq 7\) (B) no solution if \(k=7\) (C) infinite solutions if \(k \neq 7\) (D) infinite solutions if \(k=7\)
Step-by-Step Solution
Verified Answer
(D) infinite solutions if \(k = 7\).
1Step 1: Analyze the Given System of Equations
The system consists of three equations with four variables: \(x, y, z,\) and \(t\). The equations are given as follows:1. \(2x - 3y + 6z - 5t = 3\)2. \(y - 4z + t = 1\)3. \(4x - 5y + 8z - 9t = k\).Since there are more variables than equations, the system may have infinitely many solutions or may be inconsistent.
2Step 2: Check for Consistency of System
To determine when the system has a solution, check the potential inconsistency condition. This involves substituting consistent values and checking when the system cannot be satisfied:- Substitute \(k = 7\) to observe the consistency conditions.By solving, it can be identified if there's a specific condition on \(k\) that leads to no solution.
3Step 3: Simplify the System by Elimination
Attempt to eliminate variables to simplify the comparison between equations:- Use Eq. 2 \(y = 4z - t + 1\) and substitute into Eq. 1: \(2x - 3(4z - t + 1) + 6z - 5t = 3\), simplifying gives equation involving \(x\) only.- Simplify further to compare with Eq. 3.
4Step 4: Check Specific Values
Comparing equations further, substitute various specific values for \(k\):- Substitute \(k = 7\): Both Eqs 1 and 3 should simplify without contradictions.- Any other \(k eq 7\) should introduce a term that cannot be matched, confirming inconsistency.
5Step 5: Conclusion Based on Analysis
Upon checking conditions for \(k = 7\), the simultaneous equations, after involving reduced forms, can potentially satisfy each other indicating solutions exist. For \(k eq 7\), the equations become inconsistent.Thus, the solution is infinite only if \(k = 7\).
Key Concepts
Consistency of SystemsInfinite SolutionsVariables and EquationsLinear Algebra
Consistency of Systems
When working with systems of equations, a natural question to ask is whether the system is consistent or inconsistent. A consistent system is one that has at least one solution. In the context of linear equations, this typically means that the equations do not contradict each other.
If the equations within a system represent parallel lines or planes that never intersect, the system is deemed inconsistent as it has no solutions possible.
In the given exercise, the consistency is determined by the variable \(k\). By analyzing different values of \(k\), we can see when the system can possibly have a solution, thus ascertaining its consistency.
If the equations within a system represent parallel lines or planes that never intersect, the system is deemed inconsistent as it has no solutions possible.
In the given exercise, the consistency is determined by the variable \(k\). By analyzing different values of \(k\), we can see when the system can possibly have a solution, thus ascertaining its consistency.
- If \(k = 7\), the set of equations hold together harmoniously and do not contradict each other, thus confirming consistency.
- For any other value of \(k\) (\(k eq 7\)), the system loses this balance and becomes inconsistent.
Infinite Solutions
Sometimes a system of equations can have an infinite set of solutions. This typically happens when equations are dependent, meaning one is just a scalar multiple of another or a combination in more complex cases.
With more variables than equations, as seen in the exercise, there is room for infinite solutions if conditions allow. In the analyzed system, making \(k = 7\) allows all three equations to be satisfied.
This means they align perfectly, allowing for a range of variables \(x\), \(y\), \(z\), and \(t\) which satisfy each equation simultaneously.
With more variables than equations, as seen in the exercise, there is room for infinite solutions if conditions allow. In the analyzed system, making \(k = 7\) allows all three equations to be satisfied.
This means they align perfectly, allowing for a range of variables \(x\), \(y\), \(z\), and \(t\) which satisfy each equation simultaneously.
- Multiple solutions occur when conditions create a balance within the system, forming a consistent relationship between the variables.
- An infinite number of solutions reflect the presence of free variables, meaning some variables can take multiple values leading back to valid equations.
Variables and Equations
Variables and equations are fundamental in system solving. In algebra, variables depict unknowns we aim to solve for, and equations represent relationships between these variables.
The given system involves four variables: \(x\), \(y\), \(z\), and \(t\), across three equations. This setup hints at certain expected outcomes like dependence or independence of variables.
The given system involves four variables: \(x\), \(y\), \(z\), and \(t\), across three equations. This setup hints at certain expected outcomes like dependence or independence of variables.
- More variables than equations often indicate that not all variables can be uniquely determined, possibly leading to infinite solutions.
- Every equation provides an additional constraint on variables, helping define their relationships more precisely.
Linear Algebra
Linear algebra is the mathematical framework underpinning systems of linear equations. It provides methods for solving equations, analyzing matrix structures, and understanding vector spaces.
The exercise at hand, though simple in appearance, is deeply rooted in linear algebra concepts.
The exercise at hand, though simple in appearance, is deeply rooted in linear algebra concepts.
- Using linear transformations, such as substitutions, we simplify equations to reveal relationships between variables.
- Elimination, a key tool from linear algebra, helps reduce system complexity by removing variables step-by-step.
- Matrix methods or row operations often provide more organized ways to handle systems, making them easier to analyze for solutions or inconsistencies.
Other exercises in this chapter
Problem 47
Let \(A\) and \(B\) be two non-null square matrices. If the product \(A B\) is a null matrix, then (A) \(A\) is singular (B) \(B\) is singular (C) \(A\) is non-
View solution Problem 48
The rank of the matrix \(\left[\begin{array}{ccc}-1 & 2 & 5 \\ 2 & -4 & a-4 \\\ 1 & -2 & a+1\end{array}\right]\) is (A) 1 if \(a=6\) (B) 2 if \(a=1\) (C) 3 if \
View solution Problem 50
Which of the following is correct? (A) If \(A\) is a symmetric matrix, then \(A^{n}\) is symmetric, \(n \in N\) (B) If \(A\) is a skew-symmetric matrix then \(A
View solution Problem 51
If \(A\) is a non-singular matrix, then (A) \(A^{-1}\) is symmetric if \(A\) is symmetric (B) \(A^{-1}\) is skew-symmetric if \(A\) is symmetric (C) \(\left|A^{
View solution