Problem 49
Question
The protein of the haemoglobin converts \(\mathrm{CO}_{2}\) of the tissues into (a) \(\mathrm{O}_{2}\) and \(\mathrm{C}\) (b) \(\mathrm{HCO}_{3}^{-}\)and \(\mathrm{Fe}^{2+}\) (c) \(\mathrm{O}_{2}\) and \(\mathrm{CO}\) (d) \(\mathrm{HCO}_{3}^{-}\)and \(\mathrm{H}^{+}\)
Step-by-Step Solution
Verified Answer
(d) \(\mathrm{HCO}_{3}^{-}\) and \(\mathrm{H}^{+}\)
1Step 1: Understand the Function of Hemoglobin
Hemoglobin is primarily responsible for transporting oxygen from lungs to tissues and carrying carbon dioxide from tissues back to the lungs. It doesn't convert CO2 directly to O2.
2Step 2: Carbon Dioxide Transport in Blood
In the blood, carbon dioxide is transported in three ways: dissolved in plasma, chemically combined with hemoglobin, and as bicarbonate ions. The conversion of CO2 into bicarbonate is crucial as it represents the majority of CO2 transport.
3Step 3: Conversion Reaction of Carbon Dioxide
When CO2 enters the red blood cells, it reacts with water to form carbonic acid, which then dissociates into bicarbonate (\(\mathrm{HCO}_{3}^{-}\)) and hydrogen ions (\(\mathrm{H}^{+}\)). This reaction is catalyzed by the enzyme carbonic anhydrase.
4Step 4: Match the Reaction with the Options
From the conversion reaction, we get \(\mathrm{HCO}_{3}^{-}\)and \(\mathrm{H}^{+}\) as products. The correct option corresponds to these products.
Key Concepts
Carbon Dioxide TransportBicarbonate Ion FormationCarbonic Anhydrase Reaction
Carbon Dioxide Transport
Carbon dioxide ([0;34;49mCO[0m"") is a waste product formed by cells during metabolism. It needs to be expelled from the body efficiently. In the blood, [0;34;49mCO[0m"" is transported in three main ways to facilitate its removal:
- Dissolved in Plasma: A small amount of carbon dioxide dissolves directly in the blood plasma, which is the liquid component of blood.
- Bound to Hemoglobin: Carbon dioxide can bind to hemoglobin to form a compound known as carbaminohemoglobin. This allows hemoglobin to transport [0;34;49mCO[0m"" to the lungs for exhalation.
- As Bicarbonate Ions: The majority of [0;34;49mCO[0m"" in the blood is transported in the form of bicarbonate ions, a more manageable way to carry [0;34;49mCO[0m"" to the lungs.
Bicarbonate Ion Formation
When carbon dioxide enters red blood cells, with the help of water, it undergoes a transformation to bicarbonate ions ([0;34;49mHCO_{3}^{-}[0m""). This process plays a crucial role in maintaining the acid-base balance in the blood, as bicarbonate acts as a buffer. The steps for bicarbonate ion formation include:
- Firstly, [0;34;49mCO[0m"" combines with water inside red blood cells to form carbonic acid ([0;34;49mH_{2}CO_{3}[0m"").
- Subsequently, carbonic acid dissociates into bicarbonate ions ([0;34;49mHCO_{3}^{-}[0m"") and hydrogen ions ([0;34;49mH^{+}[0m"").
Carbonic Anhydrase Reaction
The conversion of carbon dioxide and water into carbonic acid is expedited by the enzyme carbonic anhydrase. This enzyme is abundant in red blood cells and ensures that the reaction occurs swiftly to meet the body's needs. Without carbonic anhydrase, the reaction would be too slow to adequately manage carbon dioxide removal. The function of carbonic anhydrase can be described in simple terms:
- Carbonic anhydrase facilitates the quick conversion of carbon dioxide and water into carbonic acid.
- It then aids in the dissociation of carbonic acid into bicarbonate ions and hydrogen ions.
- The rapidity of this reaction ensures effective buffering of blood acidity and efficient gas exchange in the lungs.
Other exercises in this chapter
Problem 47
Strecker reaction is used for synthesis of (a) alcohol (b) amino acid (c) aldehyde (d) ketone
View solution Problem 48
Denaturation of protein is caused by (a) addition of detergent (b) changing the \(\mathrm{pH}\) (c) addition of urea (d) all of these
View solution Problem 50
Which sugar is present in DNA? (a) purine only (b) deoxyribose (c) ribose (d) pyrimidine only
View solution Problem 51
Which of the following is not present in a nucleotide? (a) cytosine (b) guanine (c) adenine (d) tyrosine
View solution