Problem 49
Question
The number of oxygen atoms bonded to cach phosphorous atom in \(\mathrm{P}_{4} \mathrm{O}_{10}\) is (a) 6 (b) 5 (c) 4 (d) 3
Step-by-Step Solution
Verified Answer
The number of oxygen atoms bonded to each phosphorus atom in \( \mathrm{P}_{4} \mathrm{O}_{10} \) is 5.
1Step 1: Understanding the Molecular Formula
The chemical formula for the compound is given as \( \mathrm{P}_{4} \mathrm{O}_{10} \). It indicates that there are four phosphorus (P) atoms and ten oxygen (O) atoms in the molecule.
2Step 2: Identifying the Structure
\( \mathrm{P}_{4} \mathrm{O}_{10} \) is actually a molecular compound with a known structure. It consists of a structure where each phosphorus atom is bonded to certain oxygen atoms.
3Step 3: Dividing the Oxygen Atoms
To find the number of oxygen atoms bonded to each phosphorus atom, we take the total number of oxygen atoms (10) and consider how they are distributed among the four phosphorus atoms. This involves understanding the bonding pattern in the compound.
4Step 4: Understanding the Bonding in \( \mathrm{P}_{4} \mathrm{O}_{10} \)
In \( \mathrm{P}_{4} \mathrm{O}_{10} \), the phosphorus atoms form a tetrahedral arrangement where each phosphorus atom is bonded to three oxygen atoms directly, and two oxygen atoms are shared with another phosphorus atom as bridging atoms. Therefore, each phosphorus atom is effectively bonded to five oxygen atoms.
5Step 5: Conclusion
From the structure, we conclude that each phosphorus atom in \( \mathrm{P}_{4} \mathrm{O}_{10} \) is bonded to five oxygen atoms.
Key Concepts
Phosphorus-oxygen bondsTetrahedral arrangementMolecular formula interpretation
Phosphorus-oxygen bonds
Phosphorus-oxygen bonds are crucial in understanding the structure of many phosphorus compounds. For the molecule \( \mathrm{P}_4 \mathrm{O}_{10} \), each phosphorus atom is bonded to oxygen atoms in a specific configuration. This compound has a distinctive structural feature where each phosphorus atom forms multiple bonds with oxygen atoms.
- Each phosphorus atom is specifically bonded to three oxygen atoms via regular covalent bonds.
- Two additional oxygen atoms function as bridges, meaning they are shared between two phosphorus atoms. This results in each phosphorus effectively forming bonds with five different oxygen atoms.
Tetrahedral arrangement
In chemistry, the tetrahedral arrangement is one of the most common molecular geometries, often seen in compounds with tetrahedral shaped central atoms surrounded by other atoms. The molecule \( \mathrm{P}_4 \mathrm{O}_{10} \) follows this arrangement at the core of its molecular structure.
- The four phosphorus atoms are arranged in a tetrahedral formation, each at the corners of the tetrahedron.
- This arrangement helps in achieving stability and minimizing steric hindrance, a concept where atoms in a molecule occupy certain positions to avoid overlapping with each other while maintaining the integrity of the molecular structure.
- The oxygen atoms fill the spaces between the phosphorus atoms to complete the structure.
Molecular formula interpretation
Interpreting a molecular formula like \( \mathrm{P}_4 \mathrm{O}_{10} \) involves understanding both the count and the connection of atoms within the molecule. Breaking down this formula:
- \( \mathrm{P}_4 \) indicates that the compound contains four phosphorus atoms.
- \( \mathrm{O}_{10} \) shows there are ten oxygen atoms present in the structure.
Other exercises in this chapter
Problem 46
Amongst \(\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{H}_{2} \mathrm{Se}\) and \(\mathrm{H}_{2} \mathrm{Te}\) the one with the highest boilin
View solution Problem 48
Which one has the lowest boiling point? (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{SbH}_{3}\) (c) \(\mathrm{AsCl}_{3}\) (d) \(\mathrm{PH}_{3}\)
View solution Problem 50
d \(\mathrm{d}-\mathrm{p} \pi\) bonding is shown in (a) \(\mathrm{P}_{2} \mathrm{O}_{3}, \mathrm{P}_{2} \mathrm{O}_{5}, \mathrm{PO}_{4}^{3-}\) (b) \(\mathrm{CO}
View solution Problem 51
Which of the following fluorides does not exist? (a) \(\mathrm{PF}_{4}\) (b) \(\mathrm{SbF}_{8}\) (c) \(\mathrm{NF}_{5}\) (d) \(\mathrm{AsF}_{5}\)
View solution