Problem 49
Question
Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$y=15-2 \cos x ; \quad[0, \pi]$$
Step-by-Step Solution
Verified Answer
\(x = \cos^{-1} \left( \frac{15 - y}{2} \right)\) for \(13 \leq y \leq 17\).
1Step 1: Rearrange the Equation
Start by isolating the cosine term in the given equation. The equation is: \[ y = 15 - 2 \cos x \]Rearrange to find:\[ 2 \cos x = 15 - y \]
2Step 2: Solve for Cosine
Divide both sides by 2 to solve for \( \cos x \):\[ \cos x = \frac{15 - y}{2} \]
3Step 3: Use Inverse Cosine Function
To find \( x \), use the inverse cosine function. Thus, we have:\[ x = \cos^{-1} \left( \frac{15 - y}{2} \right) \]Ensure \(x\) is in the interval \([0, \pi]\).
4Step 4: Check Restrictions and Solution Validity
The cosine value \( \cos x \) must be within the domain of [-1, 1] for the inverse cosine function. Therefore, check:\[-1 \leq \frac{15 - y}{2} \leq 1 \]Solve these inequalities to determine the valid range for \( y \).
Key Concepts
Cosine FunctionInequalitiesRestricting Domain
Cosine Function
The cosine function is a fundamental element of trigonometry, describing the relationship between the sides of a right triangle relative to an angle. In a unit circle, it refers to the horizontal coordinate of a point. The function \(\cos x\) outputs values ranging from -1 to 1. It's periodic with a repeating cycle every \(2\pi\) radians. This periodic nature is crucial for operations such as finding angle solutions across various intervals.
In the context of solving equations involving cosine, it is essential to remember:
In the context of solving equations involving cosine, it is essential to remember:
- Cosine values represent the horizontal distance from the origin to a point on the circle.
- The cosine function decreases from 1 to -1 as the angle \(x\) moves from 0 to \(\pi\), then increases as it completes its cycle.
- You can use the inverse cosine, represented as \(\cos^{-1}\), to retrieve an angle if the cosine value is known.
Inequalities
Inequalities are expressions that establish a relationship of non-equality between two values or expressions. In trigonometric contexts, they often limit the possible values function outputs can take, ensuring valid and meaningful solutions.
Here's why understanding inequalities is key when working with functions like the cosine function:
Here's why understanding inequalities is key when working with functions like the cosine function:
- They help to ascertain the valid range of a function's output. For example, since cosine values only exist between -1 and 1, inequalities guide these limits.
- We use them to check whether computed values fit within these bounds, validating results.
- In the context of this problem, inequalities work to verify if the rearranged equation's solutions were plausible for all given conditions.
Restricting Domain
Restricting the domain of a function is necessary to create accurate and expected outputs for various trigonometric equations.
Trigonometric functions naturally have broad domains, resulting in multiple possible solutions. Restricting the domain narrows this field, allowing more precise problem-solving.
Trigonometric functions naturally have broad domains, resulting in multiple possible solutions. Restricting the domain narrows this field, allowing more precise problem-solving.
- In trigonometry, it helps to set an interval, such as \( [0, \pi] \), to limit potential solutions.
- The domain restriction ensures we find a single valid output of the inverse trig function, minimizing ambiguity.
- Such constraints also align calculations with real-world limitations or geometric interpretations, ensuring realistic solution outcomes.
Other exercises in this chapter
Problem 48
Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$y=2+3 \sin x ; \quad\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$$
View solution Problem 48
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\sin x-\cos x=0$$
View solution Problem 49
Verify the Identity. $$\ln |\sec \theta+\tan \theta|=-\ln |\sec \theta-\tan \theta|$$
View solution Problem 49
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\sin ^{2} \theta+\sin \theta-6=0$$
View solution