Problem 49
Question
Simplify each side of the following equations first, then solve. $$5-18=3 y-2 y+1$$
Step-by-Step Solution
Verified Answer
\( y = -14 \)
1Step 1: Simplify Left Side
The left side of the equation is \( 5 - 18 \). Simplify this expression: \( 5 - 18 = -13 \). Thus, the left side simplifies to \(-13\).
2Step 2: Simplify Right Side
The right side of the equation is \( 3y - 2y + 1 \). Combine like terms \( 3y - 2y \) to get \( y \). So the right side simplifies to \( y + 1 \).
3Step 3: Set Simplified Sides Equal
Now, set the simplified sides equal to each other: \(-13 = y + 1\).
4Step 4: Isolate \( y \)
To solve for \( y \), subtract 1 from both sides of the equation: \(-13 - 1 = y + 1 - 1\). This simplifies to \(-14 = y\).
5Step 5: Conclusion
We have isolated \( y \) to find that \( y = -14 \). This is the solution to the equation.
Key Concepts
Simplifying ExpressionsCombining Like TermsIsolating VariablesLinear Equations
Simplifying Expressions
Simplifying expressions is the process of making complicated expressions easier to handle and understand. In the exercise, you are given an equation with terms on both sides. To simplify, you need to perform basic arithmetic operations like addition and subtraction. For instance:
- The original expression on the left side is \( 5 - 18 \), which simplifies to \( -13 \) by subtracting 18 from 5.
- Perform similar simplifications on the right side, such as combining terms like \( 3y - 2y \) to get \( y \).
Combining Like Terms
Combining like terms is a key step in simplifying algebraic expressions, especially in equations. Like terms are those that have the same variables raised to the same power. In our exercise:
- On the right side of the equation, you have \( 3y - 2y + 1 \).
- Here, the terms \( 3y \) and \( -2y \) are like terms because they both contain the variable \( y \).
- You combine these terms by performing the subtraction \( 3y - 2y \) to get \( y \).
Isolating Variables
Isolating a variable means getting the variable on one side of the equation by itself. This is crucial to solve for the variable's value. In our example, you need to isolate \( y \) from the equation \(-13 = y + 1\). Here’s how you can do it:
- Subtract 1 from both sides: \(-13 - 1 = y + 1 - 1\)
- After this operation, you end up with \(-14 = y\)
Linear Equations
Linear equations are equations where the variable is raised only to the first power and does not appear in any denominators, exponents, or under a radical. They generally take the form \( ax + b = c \).In our exercise, the equation \(-13 = y + 1 \) is a linear equation. The key steps to solving it involve:
- First, simplify both sides by combining like terms and performing arithmetic operations.
- Next, isolate the variable to find its value.
- This results in a solution where \( y \) equals a number, in our case, \( y = -14 \).
Other exercises in this chapter
Problem 49
Rectangle \(A B C D\) has a length of 5 and a width of \(3 .\) Point \(D\) is the ordered pair \((7,2) .\) Find points \(A, B\) and \(C\). (GRAPH CANT COPY)
View solution Problem 49
Suppose \(x+y=5 .\) Find \(x\) if: $$y=-3$$
View solution Problem 49
Find the value of each of the following expressions when \(x = 5\). $$-4 x+1$$
View solution Problem 50
Rectangle \(A B C D\) has a length of 5 and a width of \(3 .\) Point \(D\) is the ordered pair \((-1,1)\). Find points \(A, B,\) and \(C\) (GRAPH CANT COPY)
View solution