Problem 49
Question
Rewrite the expression with positive exponents and simplify.\(\left(4 y^{-2}\right)\left(8 y^{4}\right)\)
Step-by-Step Solution
Verified Answer
The expression \(\left(4 y^{-2}\right) \left(8 y^{4}\right)\) with positive exponents and simplified is \(32y^2\).
1Step 1: Transform the negative exponent into a positive
A negative exponent can be turned into a positive exponent by flipping the base to the denominator of a fraction, so \(4y^{-2}\) becomes \(\frac{4}{y^2}\).
2Step 2: Multiplication without brackets
Multiply the numbers outside the brackets with their corresponding pair, so \(\frac{4}{y^2}\) * \(8y^4\) becomes \(\frac{32y^4}{y^2}\).
3Step 3: Simplify the expression
Simplify the expression by subtracting the exponents of 'y' in the numerator and the denominator. In this case, it becomes \(32(y^{4-2})=\) \(32y^2\).
Key Concepts
Negative ExponentsSimplifying ExpressionsAlgebraic Multiplication
Negative Exponents
When dealing with algebra, negative exponents can initially seem confusing, but they are quite manageable once you grasp their meaning. A negative exponent indicates that the base should be moved to the opposite side of a fraction to become positive. For instance, if you encounter \(y^{-2}\), this means \(\frac{1}{y^2}\). In the context of our exercise, the expression \(4y^{-2}\) can be rewritten as \(\frac{4}{y^2}\).
- Negative exponents signify reciprocal action.
- To convert to a positive exponent, move the base to the other side of the fraction.
- This operation does not affect the base number itself, only its exponent.
Simplifying Expressions
Simplifying expressions is a key skill in algebra that involves reducing the expression to its simplest form. It often involves combining like terms and performing basic arithmetic using the laws of exponents. In the provided exercise, we combined and simplified terms such as \(y\) by following the exponent rules.To simplify the expression \(\frac{32y^4}{y^2}\):
- Apply the law of exponents: Subtract the exponent in the denominator from the exponent in the numerator.
- This results in \(y^{4-2} = y^2\).
- The simplified form becomes \(32y^2\), which is much cleaner.
Algebraic Multiplication
Algebraic multiplication involves multiplying coefficients and following rules of exponents for powers of variables. This process can also include working with expressions in parentheses. For the expression \((4y^{-2})(8y^4)\):
- First, multiply the coefficients \(4\) and \(8\) to get \(32\).
- For the variable terms, apply the laws of exponents separately by subtracting the exponents of like bases when dividing.
- In this case, \(y^{-2}\) and \(y^4\) becomes \(y^{4-2}\), simplifying to \(y^2\).
Other exercises in this chapter
Problem 48
Find the product.\((x+y+1)(x+y-1)\)
View solution Problem 49
Simplify the expression.\(5^{1 / 2} \cdot 5^{3 / 2}\)
View solution Problem 49
Evaluate the expression.\(-3|-3|\)
View solution Problem 49
Find the least common denominator of the expressions.\(\frac{1}{x^{2}}, \frac{1}{x-1}, \frac{1}{x^{2}-x}\)
View solution