Problem 49
Question
Represent the complex number graphically, and find the standard form of the number. $$3.75\left(\cos \frac{3 \pi}{4}+i \sin \frac{3 \pi}{4}\right)$$
Step-by-Step Solution
Verified Answer
The complex number graphically represented corresponds to a point that is 3.75 units away from the origin and at an angle of \(\frac{3\pi}{4}\) radians counter-clockwise from the real axis. In standard form, the complex number is approximately \(-2.65 + 2.65i\).
1Step 1: Visualize the Complex Number
Plot the complex number on the complex plane. Start from the origin, then move along the real axis \(r = 3.75\) units (since \(r\) represents the magnitude of the complex number). Then move an angle of \(\frac{3\pi}{4}\) radians counter clock-wise (since in the polar form the argument \(\theta\) is the angle made with the positive real axis). This point represents the complex number graphically.
2Step 2: Convert Polar Form to Rectangular Form
The next step involves finding the rectangular form of the complex number. In rectangular form, a complex number is represented as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. In this case, \(a = r\cos\theta\) and \(b = r\sin\theta\). In our case, \(a = 3.75\cos(\frac{3\pi}{4})\) and \(b = 3.75\sin(\frac{3\pi}{4})\). Calculating these will give us the real and imaginary parts, respectively.
3Step 3: Calculation and Final Form
Calculate \(a\) and \(b\) using the cosine and sine of \(\frac{3\pi}{4}\) which are \(-\frac{1}{\sqrt{2}}\) and \(\frac{1}{\sqrt{2}}\) respectively. So, \(a = 3.75 \times -\frac{1}{\sqrt{2}}\) equals roughly to \(-2.65\) and \(b = 3.75 \times \frac{1}{\sqrt{2}}\) equals roughly to \(2.65\). Hence, the rectangular (or standard) form of the complex number is approximately \(-2.65 + 2.65i\).
Key Concepts
Polar CoordinatesRectangular FormConversion of Complex Numbers
Polar Coordinates
Polar coordinates are a way to represent complex numbers, which are numbers with both real and imaginary parts. In polar coordinates, a complex number is expressed as a combination of a magnitude (or modulus) and an angle (or argument). This representation can be very useful for visualizing and performing operations on complex numbers.
Typically denoted as \( r(\cos \theta + i \sin \theta) \) or \( r \operatorname{cis} \theta \), the polar form highlights the number’s rotation and stretch from the origin. Here:
Typically denoted as \( r(\cos \theta + i \sin \theta) \) or \( r \operatorname{cis} \theta \), the polar form highlights the number’s rotation and stretch from the origin. Here:
- \(r\) is the modulus or the distance of the point from the origin in the complex plane.
- \(\theta\) is the argument or the angle from the positive real axis, measured counterclockwise.
Rectangular Form
The rectangular form of a complex number describes it in terms of its real and imaginary components. You might find this form written as \(a + bi\), where \(a\) represents the real part, and \(b\) is the coefficient of the imaginary part \(i\).
Converting from polar to rectangular involves calculating the actual values of these components using trigonometric functions. Specifically:
Converting from polar to rectangular involves calculating the actual values of these components using trigonometric functions. Specifically:
- The real part \(a\) is determined by \(a = r \cos \theta\).
- The imaginary part \(b\) is found by \(b = r \sin \theta\).
Conversion of Complex Numbers
To effectively work with complex numbers, it is often necessary to convert between polar and rectangular forms. Each form has its advantages depending on the mathematical operation you're performing.
For conversion from polar to rectangular form as previously mentioned:
Understanding how to switch between these forms not only helps in solving complex equations but also gives a deeper insight into the behavior of complex numbers in various applications like electronics and physics.
For conversion from polar to rectangular form as previously mentioned:
- Find the real component by multiplying the modulus \(r\) with the cosine of the argument \(\theta\).
- Compute the imaginary component by multiplying the modulus \(r\) with the sine of the argument \(\theta\).
Understanding how to switch between these forms not only helps in solving complex equations but also gives a deeper insight into the behavior of complex numbers in various applications like electronics and physics.
Other exercises in this chapter
Problem 49
Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.$$\mathbf{v}=\langle-1,1\rangle$$.
View solution Problem 49
Determine whether u and v are orthogonal, parallel, or neither. $$\begin{aligned} &\mathbf{u}=-\frac{3}{5} \mathbf{i}+\frac{7}{10} \mathbf{j}\\\ &\mathbf{v}=12
View solution Problem 50
Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1. $$\mathbf{v}=\langle-2,2\rangle$$
View solution Problem 50
Determine whether u and v are orthogonal, parallel, or neither. $$\begin{aligned} &\mathbf{u}=-\frac{9}{10} \mathbf{i}+3 \mathbf{j}\\\ &\mathbf{v}=-5 \mathbf{i}
View solution