Problem 49
Question
\mathrm{\\{} I n ~ P r o b l e m s ~ , ~ g r a p h ~ t h e ~ l i n e ~ \(\boldsymbol{N}_{t+1}=\boldsymbol{R} N_{t}\) in the \(\boldsymbol{N}_{t}-\boldsymbol{N}_{t+1}\) plane for the indicated value of \(R\) and locate the points \(\left(N_{t}, N_{t+1}\right), t=0,1\), and 2, for the given value of \(N_{0}\) $$ R=\frac{1}{3}, N_{0}=81 $$
Step-by-Step Solution
Verified Answer
Plot points (81, 27) and (27, 9) on the graph.
1Step 1: Understanding the Equation
The equation given is \( N_{t+1} = R N_{t} \). This represents a linear relationship where \( N_{t+1} \) is a function of \( N_{t} \) scaled by the factor \( R \). For this problem, \( R = \frac{1}{3} \) and \( N_{0} = 81 \). This means to calculate \( N_{t+1} \), you multiply \( N_{t} \) by \( \frac{1}{3} \).
2Step 2: Calculating \( N_{1} \)
Substitute \( N_{0} = 81 \) into the equation: \( N_{1} = \frac{1}{3} \times 81 = 27 \). The first point to plot is \((N_{0}, N_{1}) = (81, 27)\).
3Step 3: Calculating \( N_{2} \)
Use \( N_{1} = 27 \) to find \( N_{2} \): \( N_{2} = \frac{1}{3} \times 27 = 9 \). The second point to plot is \((N_{1}, N_{2}) = (27, 9)\).
4Step 4: Visualizing the Graph
Plot the calculated points \((81, 27)\), \((27, 9)\) on the \( N_{t}-N_{t+1} \) plane. The line graph will show a decrease in \( N_{t} \) values, reflecting the reduction factor \( R = \frac{1}{3} \).
Key Concepts
Graphing in MathematicsSequence and Series AnalysisExponential Decay in Biology
Graphing in Mathematics
Graphing is a fundamental skill in mathematics that involves plotting data points on a coordinate plane. This exercise uses the linear difference equation \( N_{t+1} = R N_{t} \), where \( R = \frac{1}{3} \) and \( N_{0} = 81 \). Here, we explore how these variables create a graph that shows a relationship between consecutive terms of a sequence.
To begin graphing, identify the initial point \( (N_0, N_1) = (81, 27) \). This point is derived by multiplying \( N_0 \) by \( R \). For each subsequent point, the current value \( N_t \) is multiplied by \( R \) to find \( N_{t+1} \).
To begin graphing, identify the initial point \( (N_0, N_1) = (81, 27) \). This point is derived by multiplying \( N_0 \) by \( R \). For each subsequent point, the current value \( N_t \) is multiplied by \( R \) to find \( N_{t+1} \).
- Point 1: \( (81, 27) \)
- Point 2: \( (27, 9) \)
Sequence and Series Analysis
In mathematics, sequence and series analysis is a method used to evaluate the behavior of numbers arranged in a particular order. Here we observe a linear difference sequence as described by the equation \( N_{t+1} = R N_{t} \). This insight helps us understand how series behave over time, particularly with changes in terms.
For the given values, \( R = \frac{1}{3} \), which acts as a reduction factor affecting the entire sequence. Starting from \( N_0 = 81 \), each term in the sequence is found by multiplying the previous term by \( \frac{1}{3} \). As seen in our example:
For the given values, \( R = \frac{1}{3} \), which acts as a reduction factor affecting the entire sequence. Starting from \( N_0 = 81 \), each term in the sequence is found by multiplying the previous term by \( \frac{1}{3} \). As seen in our example:
- \( N_1 = 27 \)
- \( N_2 = 9 \)
Exponential Decay in Biology
Exponential decay is a critical concept in biology, describing processes that decrease rapidly over time. The scientific phenomenon can be modeled mathematically by equations similar to the one explored: \( N_{t+1} = R N_{t} \).
In this context, \( R = \frac{1}{3} \) represents a decay factor, leading to a decline in population or concentration levels with each time step. For example, if modeling the decay of a substance or population, \( N_0 = 81 \) might represent an initial concentration or number of individuals. Over time, this value reduces as shown:
In this context, \( R = \frac{1}{3} \) represents a decay factor, leading to a decline in population or concentration levels with each time step. For example, if modeling the decay of a substance or population, \( N_0 = 81 \) might represent an initial concentration or number of individuals. Over time, this value reduces as shown:
- From 81 to 27 (in one time step)
- Then from 27 to 9
Other exercises in this chapter
Problem 49
Investigate the behavior of the discrete logistic equation $$ x_{t+1}=R_{0} x_{t}\left(1-x_{t}\right) $$ Compute \(x_{t}\) for \(t=0,1,2, \ldots, 20\) for the g
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Write the first five terms of the sequence \(\left\\{a_{n}\right\\}\), \(n=0,1,2,3, \ldots\), and find \(\lim _{n \rightarrow \infty} a_{n^{*}}\) $$ a_{n}=\frac
View solution Problem 50
Investigate the behavior of the discrete logistic equation $$ x_{t+1}=R_{0} x_{t}\left(1-x_{t}\right) $$ Compute \(x_{t}\) for \(t=0,1,2, \ldots, 20\) for the g
View solution Problem 50
Write the first five terms of the sequence \(\left\\{a_{n}\right\\}\), \(n=0,1,2,3, \ldots\), and find \(\lim _{n \rightarrow \infty} a_{n^{*}}\) $$ a_{n}=\frac
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