Problem 49
Question
In how many ways can 6 transfer students be assigned to seats in a classroom that has 10 empty seats?
Step-by-Step Solution
Verified Answer
There are 151,200 ways to assign the 6 students to 10 seats.
1Step 1: Understanding the Problem
We need to assign 6 transfer students to 10 empty seats in a classroom. This is a problem of counting the arrangements, which can be solved using permutations.
2Step 2: Choosing Seats for Students
First, we need to choose 6 seats out of the 10 available seats for the students. The number of ways to choose 6 seats from 10 is given by the combination formula: \[ \binom{10}{6} \]
3Step 3: Calculating Combinations
Calculate the number of combinations. \[ \binom{10}{6} = \frac{10!}{6!(10-6)!} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} = 210 \]
4Step 4: Assigning Students to Chosen Seats
Once 6 seats are chosen, each seat can be filled by any of the 6 students. Thus, the number of ways to arrange 6 students in 6 seats is given by 6! (factorial of 6). Therefore:\[ 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 \]
5Step 5: Calculating Total Arrangements
Multiply the number of ways to choose the seats by the number of ways to arrange the students in those seats:\[ 210 \times 720 = 151,200 \]
6Step 6: Conclusion
The total number of ways the 6 transfer students can be assigned to 10 seats is 151,200.
Key Concepts
CombinationsFactorialArrangementsCounting Problems
Combinations
Combinations allow us to select items from a larger set where the order does not matter. In our case, we need to choose 6 seats out of 10 available, which is a perfect example of combinations. The formula to calculate combinations is: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]
- Here, \(n\) is the total number of items to choose from, which is 10 seats.
- \(k\) is the number of items to choose, which is 6 seats.
Factorial
Factorial is a concept often denoted by an exclamation mark \(!\), and it represents the product of an integer and all the integers below it. For instance, the factorial of 6, expressed as 6!, is:\[6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\]Factorials are essential for calculating permutations and combinations, like in the combination formula given above.
- In permutations, factorial helps us determine how to arrange a subset of items.
- In combinations, factorial allows us to calculate how many ways items can be selected.
Arrangements
Arrangements are about figuring out how to order or position a subset of items from a larger set once these items are selected. Once we have chosen 6 seats from the 10 available, arranging 6 students in these seats is a matter of permutation, calculated using factorial. Since each seat can be filled by any of the 6 students, we use the factorial of 6 (6!) to find the number of ways to arrange them:\[6! = 720\]
- Each arrangement of students determines a different and unique seating order.
- This highlights the difference between combinations (choosing items) and arrangements (ordering selected items).
Counting Problems
Counting problems are mathematical queries that require us to find the number of ways certain events can occur under a specific set of conditions. They are fundamental in understanding the breadth of possibilities in different scenarios.
- Many counting problems use permutations and combinations as tools to arrive at the solution.
- In our case, we first use combinations to select the seats and permutations for arranging students.
Other exercises in this chapter
Problem 47
There are 12 boys and 13 girls assigned to a class. In how many ways can 2 boys and 3 girls be selected to transfer to a different class?
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From a standard deck of 52 cards, how many hands of 5 cards can be dealt?
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A local convenience store hires three students to work after school. Next month, there are 20 days on which they will work. Alex will work 8 days, Rosa will wor
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