Problem 49
Question
If possible, solve the system of linear equations and check your answer. $$ \begin{array}{rr} 3 x-2 y= & 5 \\ -6 x+4 y= & -10 \end{array} $$
Step-by-Step Solution
Verified Answer
The system has infinitely many solutions; any point on the line satisfies both equations.
1Step 1: Identify the System of Equations
The system of equations given are:\[ 3x - 2y = 5 \] and \[ -6x + 4y = -10 \]
2Step 2: Check for Linearity Dependence
Notice that the second equation is a multiple of the first. Multiply the first equation by 2 to see if it matches the second equation. After multiplication, \[ 2(3x - 2y) = 2(5) \] gives \[ 6x - 4y = 10 \], which, when rearranged, results in \[ -6x + 4y = -10 \] being equivalent to the second equation. This indicates that the equations are dependent.
3Step 3: Interpret the Results
Since one equation is a multiple of the other, the two equations represent the same line. Therefore, the system has infinitely many solutions, where solutions can be any point on the line.
4Step 4: Verify an Example Solution
To verify, take an arbitrary value of \(x\), say \(x = 1\), and substitute it into either equation. Using the first equation: \[ 3(1) - 2y = 5 \Rightarrow 3 - 2y = 5 \Rightarrow -2y = 2 \Rightarrow y = -1 \]. The point \((1, -1)\) is a solution. Substitute into the second equation to verify: \[ -6(1) + 4(-1) = -10 \Rightarrow -6 - 4 = -10 \], which confirms that the point is indeed a solution.
Key Concepts
System of EquationsIndependent SolutionsDependent Equations
System of Equations
A system of equations refers to a set of two or more equations that have the same variables. In our original exercise problem, we are working with two equations, which means they form a system:
There are several possible outcomes when solving a system of linear equations:
- Equation 1: \(3x - 2y = 5\)
- Equation 2: \(-6x + 4y = -10\)
There are several possible outcomes when solving a system of linear equations:
- One solution: This occurs when the lines intersect at a single point.
- No solution: This happens when the lines are parallel and never intersect.
- Infinitely many solutions: This arises when the lines coincide, representing the same line.
Independent Solutions
In the context of a system of linear equations, independent solutions occur when each equation in the system provides distinct information, meaning the lines intersect at exactly one point. When we solve such systems, we are generally looking for this point of intersection, which represents the unique solution that satisfies both equations.
For independently solvable systems, you can use several methods:
For independently solvable systems, you can use several methods:
- Substitution Method: Solve for one variable in terms of the other, and substitute it back into the second equation.
- Elimination Method: Add or subtract equations to eliminate one variable, making it easier to solve for the other.
- Graphical Method: Graph both equations and find the intersection point visually.
Dependent Equations
Dependent equations occur when one equation in the system is a multiple of the other, leading to them representing the same line. This implies that all the solutions to one equation are solutions to the other as well, resulting in infinitely many solutions. Essentially, each equation provides the same information about the variables.
In our example:
When studying systems with dependent equations, it's crucial to verify if one equation can be derived from the other. Once identified, every point on the line \(3x - 2y = 5\) is a solution because the system describes the exact same line twice. Hence, instead of finding a unique solution, any point on this line could be considered a valid solution, leading to infinitely many solutions. For such systems, establishing one of the dependent equations in terms of a parameter can help describe the complete solution set.
In our example:
- Equation 1: \(3x - 2y = 5\)
- Equation 2: \(-6x + 4y = -10\)
When studying systems with dependent equations, it's crucial to verify if one equation can be derived from the other. Once identified, every point on the line \(3x - 2y = 5\) is a solution because the system describes the exact same line twice. Hence, instead of finding a unique solution, any point on this line could be considered a valid solution, leading to infinitely many solutions. For such systems, establishing one of the dependent equations in terms of a parameter can help describe the complete solution set.
Other exercises in this chapter
Problem 49
Complete the following. (A) Write the system in the form \(A X=B\). (B) Solve the system by finding \(A^{-1}\) and then using the equation \(\boldsymbol{X}=\bol
View solution Problem 49
Solve the system, if possible. $$ \begin{array}{rr} 5 x-2 y+z= & 5 \\ x+y-2 z= & -2 \\ 4 x-3 y+3 z= & 7 \end{array} $$
View solution Problem 50
Use the given \(A\) and \(B\) to evaluate each expression. $$A=\left[\begin{array}{rrr}3 & -2 & 4 \\\5 & 2 & -3 \\\7 & 5 & 4\end{array}\right], B=\left[\begin{a
View solution Problem 50
Complete the following. (A) Write the system in the form \(A X=B\). (B) Solve the system by finding \(A^{-1}\) and then using the equation \(\boldsymbol{X}=\bol
View solution