Problem 49
Question
Give the integral formulas for area and arc length in polar coordinates.
Step-by-Step Solution
Verified Answer
The integral formula for area in Polar Coordinates is \[\int_{a}^{b} \frac{1}{2} {r(\theta)}^{2} \, d\theta\] and for arc length is \[\int_{a}^{b} \sqrt{(r(\theta))^2 + \left(\frac{dr}{d\theta}\right)^2} \,d\theta\].
1Step 1: Formulate the Integral Formula for Area in Polar Coordinates
To find the area between two radii, the integral formula in polar coordinates is: \[\int_{a}^{b} \frac{1}{2} {r(\theta)}^{2} \,d\theta\] where \(a\) and \(b\) are the limits of integration, \(r(\theta)\) is the polar function, and \(\theta\) is the angle.
2Step 2: Formulate the Integral Formula for Arc Length in Polar Coordinates
To find the arc length, the integral formula in polar coordinates is: \[\int_{a}^{b} \sqrt{(r(\theta))^2 + \left(\frac{dr}{d\theta}\right)^2} \,d\theta\] where \(a\) and \(b\) are the limits of integration, \(r(\theta)\) is the polar function and \(\frac{dr}{d\theta}\) is its derivative with respect to \(\theta\).
Other exercises in this chapter
Problem 48
Find the arc length of the curve on the given interval. $$ x=\arcsin t, \quad y=\ln \sqrt{1-t^{2}} \quad 0 \leq t \leq \frac{1}{2} $$
View solution Problem 49
$$ \text { State the definition of a smooth curve } $$
View solution Problem 49
Find the arc length of the curve on the given interval. $$ x=\sqrt{t}, \quad y=3 t-1 \quad 0 \leq t \leq 1 $$
View solution Problem 49
Use a graphing utility to (a) graph the polar equation, (b) draw the tangent line at the given value of \(\boldsymbol{\theta}\), and (c) find \(d y / d x\) at t
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