Problem 49
Question
For the following exercises, create a system of linear equations to describe the behavior. Then, calculate the determinant. Will there be a unique solution? If so, find the unique solution. Two numbers add up to \(56 .\) One number is 20 less than the other.
Step-by-Step Solution
Verified Answer
The unique solution is \( x = 18 \) and \( y = 38 \).
1Step 1: Define Variables
To begin solving the problem, let's define our variables. Let \( x \) be the first number and \( y \) be the second number.
2Step 2: Set Up Equations
Based on the problem statement, we can set up two equations:1. The sum of the two numbers is given by the equation \( x + y = 56 \).2. One number is 20 less than the other, described by the equation \( x = y - 20 \).
3Step 3: Form the System of Equations
The system of equations is:\[ \begin{align*} x + y &= 56, \ x &= y - 20. \end{align*} \]
4Step 4: Write in Matrix Form
Express the system as a matrix equation:\[ \begin{pmatrix} 1 & 1 \ 1 & -1 \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} = \begin{pmatrix} 56 \ -20 \end{pmatrix} \]
5Step 5: Calculate the Determinant
The determinant for the matrix \( A = \begin{pmatrix} 1 & 1 \ 1 & -1 \end{pmatrix} \) is calculated as follows:\[ \text{det}(A) = (1)(-1) - (1)(1) = -1 - 1 = -2 \]
6Step 6: Determine Unique Solution
Since the determinant is non-zero (\(-2\)), there is a unique solution to the system of equations.
7Step 7: Solve the System of Equations
Substitute \( x = y - 20 \) into the first equation: \[ y - 20 + y = 56 \]Simplify: \[ 2y - 20 = 56 \]Add 20 to both sides: \[ 2y = 76 \]Divide by 2: \[ y = 38 \]Substitute \( y = 38 \) back to find \( x \): \[ x = 38 - 20 = 18 \]
8Step 8: Verify the Solution
Check the original equations:1. \( x + y = 18 + 38 = 56 \) ✔️2. \( x = y - 20 = 38 - 20 = 18 \) ✔️Both equations are satisfied with \( x = 18 \) and \( y = 38 \).
Key Concepts
Determinant CalculationUnique SolutionMatrix Representation
Determinant Calculation
The determinant is a critical value that helps to determine whether a system of linear equations has a unique solution. To find it, we look at the coefficient matrix of our system of equations. In this particular problem, our system is represented by the matrix:
- \( \begin{pmatrix} 1 & 1 \ 1 & -1 \end{pmatrix} \)
- \( \text{det}(A) = (1)(-1) - (1)(1) \)
- = -1 - 1 \
- = -2
Unique Solution
A unique solution occurs when a system of linear equations intersects at exactly one point in the solution space. For this to happen, the determinant of the coefficient matrix must be non-zero. For our system of equations:
- \( x + y = 56 \)
- \( x = y - 20 \)
- \(y - 20 + y = 56 \)
- \(2y = 76 \)
- \(y = 38 \)
- \(x = y - 20 = 18\)
Matrix Representation
Matrix representation is a powerful method used to express a system of equations. It allows us to solve systems efficiently using computational techniques. For the given problem, where two numbers satisfy the system:
- \( x + y = 56 \)
- \( x = y - 20 \)
- \( A \) is the coefficient matrix \( \begin{pmatrix} 1 & 1 \ 1 & -1 \end{pmatrix} \)
- \( \vec{x} \) is the column matrix of variables \( \begin{pmatrix} x \ y \end{pmatrix} \)
- \( \vec{b} \) is the constant column matrix \( \begin{pmatrix} 56 \ -20 \end{pmatrix} \)
Other exercises in this chapter
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