Problem 49
Question
For a reaction taking place in a container in equilibrium with its surroundings, the effect of temperature on its equilibrium constant \(K\) in terms of change in entropy is described by [Adv. 2017] (a) With increase in temperature, the value of \(K\) for exothermic reaction decreases because the entropy change of the system is positive (b) With increase in temperature, the value of \(K\) for endothermic reaction increases because unfavourable change in entropy of the surroundings decreases (c) With increase in temperature, the value of \(K\) for endothermic reaction increases because the entropy change of the system is negative (d) With increase in temperature, the value of \(K\) for exothermic reaction decreases because favourable change in entropy of the surroundings decreases
Step-by-Step Solution
VerifiedKey Concepts
Equilibrium Constant
- If \(K\) is large, products are favored at equilibrium.
- If \(K\) is small, reactants are favored at equilibrium.
Endothermic Reactions
In the context of the Van't Hoff equation, as temperature rises, the equilibrium constant \(K\) increases for endothermic reactions. This happens because the system absorbs more heat, making the forward reaction more favorable. Thus, more products are formed.
Exothermic Reactions
According to the Van't Hoff equation, as temperature increases, the equilibrium constant \(K\) decreases for exothermic reactions. The negative enthalpy term becomes less pronounced, shifting the balance towards the formation of reactants rather than products.
Entropy Change
- For endothermic reactions, an increase in system entropy is often observed, which complements the absorption of heat.
- For exothermic reactions, entropy in the surroundings increases due to the release of heat.
Temperature Effect on Equilibrium
- For endothermic reactions, increasing temperature shifts the equilibrium position towards products, increasing \(K\).
- For exothermic reactions, increasing temperature shifts the equilibrium position towards reactants, decreasing \(K\).