Problem 49
Question
Find the exact distance between each pair of points. \((-2,1),(3,4)\)
Step-by-Step Solution
Verified Answer
The exact distance between the points is \( \sqrt{34} \).
1Step 1: Identify the point coordinates
We are given two points, \((-2,1)\) and \(3,4)\). Let's identify the coordinates of each point. The first point, \((-2,1)\), has coordinates \(x_1 = -2\) and \(y_1 = 1\). The second point, \(3,4)\), has coordinates \(x_2 = 3\) and \(y_2 = 4\).
2Step 2: Apply the Distance Formula
We use the distance formula to find the distance between two points \((x_1, y_1)\) and \(x_2, y_2)\). The formula is written as: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]Plug the coordinates into the formula to find the distance.
3Step 3: Calculate the difference of x-coordinates
Subtract the x-coordinate of the first point from the x-coordinate of the second point: \(x_2 - x_1 = 3 - (-2) = 3 + 2 = 5\)
4Step 4: Calculate the difference of y-coordinates
Subtract the y-coordinate of the first point from the y-coordinate of the second point: \(y_2 - y_1 = 4 - 1 = 3\)
5Step 5: Compute the squares of the differences
Now, square the differences found in the previous steps: \[(x_2 - x_1)^2 = 5^2 = 25\] \[(y_2 - y_1)^2 = 3^2 = 9\]
6Step 6: Add the squares of the differences
Add the squared differences:\[25 + 9 = 34\]
7Step 7: Find the square root of the sum
To find the distance, take the square root of 34:\[ d = \sqrt{34} \] It cannot be simplified further into an integer or a simpler radical form.
Key Concepts
Coordinate GeometryDistance Between PointsPythagorean Theorem
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system. It connects algebra and geometry by utilizing coordinate planes to illustrate points, lines, and figures. This makes it easier to solve geometric problems using algebraic equations. In a 2D plane, we use an x-axis (horizontal) and a y-axis (vertical) to pinpoint the location of points. For example, in our exercise, the points
- er{-2, 1) and (3,4) represent two locations on this plane.
- erCoordinates allow us to measure various aspects like distance, slope, and area directly from a mathematical equation.
Distance Between Points
Understanding how to calculate the distance between two points on a coordinate plane is fundamental in geometry. The distance is the length of the straight line that directly connects two points. Imagine you have two points, such as er(-2, 1) and (3,4). The distance between them can be found using the distance formula, which is derived from the Pythagorean theorem. The formula is written as: d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}Simply plug in the coordinates into the formula: Subtract the x-coordinates: \(3 - (-2) = 5\) Subtract the y-coordinates: \(4 - 1 = 3\) Square these differences: \(5^2 = 25\) and \(3^2 = 9\) Add them together: \(25 + 9 = 34\) Finally, compute the square root to find the distance: \(d = \sqrt{34}\) This process ensures that the distance calculation is clear, consistent, and reliable regardless of the specific points involved.
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry that relates the sides of a right triangle. It states that for a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. Mathematically, it's expressed as: c^2 = a^2 + b^2But how does this relate to finding the distance between two points in coordinate geometry? When you have two points, such as er(-2, 1) and (3,4), envision creating a right triangle where:
- The horizontal distance between x-coordinates \((3 - (-2) = 5)\) forms one leg of the triangle.
- The vertical distance \((4 - 1 = 3)\) forms the other leg.
Other exercises in this chapter
Problem 48
Solve each equation. $$ \sqrt{m+4}=\sqrt{2 m-5} $$
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Square or cube each quantity and simplify the result. $$ (-2 \sqrt[3]{2 x^{2}})^{3} $$
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Simplify each expression. All variables represent positive real numbers. $$ \frac{\sqrt[3]{48 x^{7}}}{\sqrt[3]{6 x}} $$
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Solve each equation. $$ 2 \sqrt{4 x+1}=\sqrt{x+4} $$
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