Problem 49
Question
Find the domain of the function. \(f(x)=\ln (7-x)+\ln (x-4)\)
Step-by-Step Solution
Verified Answer
The domain of the function is \((4, 7)\).
1Step 1: Understanding Logarithmic Functions
The function is composed of two logarithmic functions: \( \ln(7-x) \) and \( \ln(x-4) \). For the logarithm to be defined, the arguments must be positive: \( 7-x > 0 \) and \( x-4 > 0 \).
2Step 2: Finding Constraints for Each Logarithm
For \( \ln(7-x) \) to be defined, \( 7-x > 0 \). Solving this inequality: \( x < 7 \). For \( \ln(x-4) \) to be defined, \( x-4 > 0 \). Solving this inequality: \( x > 4 \).
3Step 3: Finding the Intersection of Solutions
The domain is determined by the intersection of the solutions to both inequalities. From \( x < 7 \) and \( x > 4 \), the domain of \( f(x) \) is \( 4 < x < 7 \).
4Step 4: Expressing the Domain in Interval Notation
Write the domain as an interval: The function \( f(x) = \ln(7-x) + \ln(x-4) \) is defined for \( x \) in the interval \((4, 7)\).
Key Concepts
Understanding Logarithmic InequalitiesConverting to Interval NotationExploring the Intersection of Inequalities
Understanding Logarithmic Inequalities
Logarithmic inequalities involve expressions where a logarithm function is compared to another value. Solving these inequalities works similarly to solving quadratic or linear inequalities. The primary rule is that the argument of a logarithmic function must be greater than zero— logarithms of non-positive numbers are undefined. For the function \(f(x)=\ln (7-x)+\ln (x-4)\), both \(7-x\) and \(x-4\) must be individually greater than zero to keep the function valid and solve the inequalities:
- \(7-x > 0\) implies \(x < 7\)
- \(x-4 > 0\) implies \(x > 4\)
Converting to Interval Notation
Once you've solved the separate inequalities from the logarithmic function, the next step is to express the domain in a compact form, known as interval notation. This notation uses brackets to show that numbers within the specified range are included or excluded.For the function \(f(x)=\ln (7-x)+\ln (x-4)\), the inequalities \(x < 7\) and \(x > 4\) need to be combined. The solution to both gives us the interval \((4, 7)\). Note that:
- Parentheses, \(()\), are used to indicate that the endpoints are not included.
- In this example, both 4 and 7 are not part of the domain, only values between them.
Exploring the Intersection of Inequalities
Finding the intersection of inequalities like \(x<7\) and \(x>4\) essentially involves identifying the common values that satisfy both conditions. This means looking for a range where both inequalities overlap. To express the overlapping solution, imagine a number line:
- \(x<7\) indicates all numbers to the left of 7.
- \(x>4\) indicates all numbers to the right of 4.
- The intersection is the part of the line where both constraints hold true: \(4 < x < 7\).
Other exercises in this chapter
Problem 48
Find the domain of the function. \(f(x)=\log \left(\frac{x^{2}+9 x+18}{4 x-20}\right)\)
View solution Problem 49
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View solution Problem 50
Find the domain of the function. \(f(x)=\ln (4 x-20)+\ln \left(x^{2}+9 x+18\right)\)
View solution Problem 51
Find the domain of the function. \(f(x)=\log \left(x^{2}+x+1\right)\)
View solution