Problem 49
Question
Explain why the equation \(\sec \theta=0\) has no solutions.
Step-by-Step Solution
Verified Answer
The equation has no solutions because \(\frac{1}{\cos \theta} = 0\) is undefined.
1Step 1: Understanding the Secant Function
The secant function, represented as \(\sec \theta\), is the reciprocal of the cosine function. This means \(\sec \theta = \frac{1}{\cos \theta}\). For \(\sec \theta\) to equal zero, \(\frac{1}{\cos \theta} = 0\) must be true.
2Step 2: Analyzing the Reciprocal Property
The expression \(\frac{1}{\cos \theta}\) can only be zero if \(\cos \theta\) is undefined or does not exist. However, a reciprocal of zero implies division by zero, which is undefined in mathematics.
3Step 3: Exploring Cosine Values
Since \(\cos \theta\) can never be zero for \(\sec \theta\) to exist, we know that there are no values of \(\theta\) that make \(\cos \theta\) undefined in the real number system.
4Step 4: Concluding No Solutions Exist
Since it is impossible for \(\frac{1}{\cos \theta}\) to equal zero, the equation \(\sec \theta = 0\) has no solutions within the set of real numbers.
Key Concepts
Reciprocal of CosineUndefined in MathematicsTrigonometric Equations
Reciprocal of Cosine
The secant function, denoted as \(\sec \theta\), is known for being the reciprocal of the cosine function. Mathematically, we express this relationship as \(\sec \theta = \frac{1}{\cos \theta}\).
This fundamental principle means that the value of \(\sec \theta\) depends on the value of \(\cos \theta\).
In simpler terms, whenever you need to calculate the secant of an angle \(\theta\), you first determine the cosine of that angle and then take its reciprocal.
This fundamental principle means that the value of \(\sec \theta\) depends on the value of \(\cos \theta\).
In simpler terms, whenever you need to calculate the secant of an angle \(\theta\), you first determine the cosine of that angle and then take its reciprocal.
- If \(\cos \theta\) is a number like 1 or -1, \(\sec \theta\) becomes 1 or -1, respectively.
- However, if \(\cos \theta\) were to be zero, we encounter a mathematical dilemma, as division by zero is undefined.
Undefined in Mathematics
In mathematics, there is a concept of expressions that are undefined. A common situation where this arises is division by zero.
For any non-zero number \(a\), the expression \(\frac{a}{0}\) does not exist in the realm of real numbers. This leads to an important rule: any solution implying division by zero is considered undefined.
For any non-zero number \(a\), the expression \(\frac{a}{0}\) does not exist in the realm of real numbers. This leads to an important rule: any solution implying division by zero is considered undefined.
- When working with trigonometric functions like secant, understanding when an expression becomes undefined is crucial.
- If \(\cos \theta\) equals zero, then \(\sec \theta = \frac{1}{\cos \theta}\) can't be computed, as it would require dividing by zero.
- This means that for \(\sec \theta\) to equal zero, it would imply \(\frac{1}{0}\), which is a contradiction and hence not possible.
Trigonometric Equations
Trigonometric equations are mathematical equations that involve trigonometric functions like sine, cosine, and secant. Solving these equations typically involves identifying the values of the angle \(\theta\) that make the equation true.
A general approach includes considering the properties and graphs of trigonometric functions such as periodicity and amplitude.
A general approach includes considering the properties and graphs of trigonometric functions such as periodicity and amplitude.
- For instance, in the equation \(\sec \theta = 0\), the goal is to find values of \(\theta\) where this condition holds true.
- However, understanding that \(\sec \theta = \frac{1}{\cos \theta}\), the equation can only be solved if \(\frac{1}{\cos \theta}\) truly can equate to zero, which is not feasible given the properties of cosine.
- This renders certain trigonometric equations, like \(\sec \theta = 0\), inherently unsolvable within the real number system.
Other exercises in this chapter
Problem 48
State the vertical shift, equation of the midline, amplitude, and period for each function. Then graph the function. (Lesson 142\()\) \(y=\sin \theta-1\)
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Solve each equation. $$ \operatorname{Arccos} \frac{\sqrt{2}}{2}=x $$
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The carrier wave for a certain FM radio station can be modeled by the equation \(y=A \sin \left(10^{7} \cdot 2 \pi t\right),\) where \(A\) is the amplitude of t
View solution Problem 49
Verify that each of the following is an identity. \(\sin \theta(\sin \theta+\csc \theta)=2-\cos ^{2} \theta\)
View solution