Problem 49
Question
Decide if the statements in Problems are true or false. Give an explanation for your answer. If the Taylor polynomial of degree 2 for \(f(x)\) near \(x=0\) is \(P_{2}(x)=1+x-x^{2},\) then \(f(x)\) is concave up near \(x=0\)
Step-by-Step Solution
Verified Answer
False, since the second derivative is negative, indicating concave down.
1Step 1: Define concavity
A function is concave up on an interval if its second derivative is positive on that interval.
2Step 2: Identify f''(x) from the Taylor polynomial
Given the Taylor polynomial, \( P_{2}(x) = 1 + x - x^2 \), we can identify coefficients that relate to the derivatives of \( f(x) \):- The coefficient of \( x^2 \), which is \( -1 \), corresponds to \( \frac{f''(0)}{2!} \).- This means \( \frac{f''(0)}{2!} = -1 \). Solving gives \( f''(0) = -2 \).
3Step 3: Determine concavity from f''(0)
Since \( f''(0) = -2 \) is negative, the function \( f(x) \) is concave down near \( x=0 \).
4Step 4: Conclude the truth of the statement
Based on the calculation in Step 3, since \( f''(x) < 0 \) near \( x=0 \), \( f(x) \) is concave down and therefore the statement 'concave up' is false.
Key Concepts
ConcavitySecond Derivative TestCalculus Education
Concavity
Understanding concavity is crucial in calculus, especially when analyzing the behavior of functions. A function is termed **concave up** if its graph opens upwards like a cup. This typically suggests that the slopes of the tangent lines to the graph are increasing.
In simpler terms, if you picture a bowl, the bowl shape when the lip is upwards signifies concavity up. On the other hand, a function is **concave down** if its graph opens downwards, similar to an upside-down bowl. When the function is concave down, this means the slopes of the tangent lines are decreasing. The sign of the second derivative, denoted as \( f''(x) \), determines the concavity:
In simpler terms, if you picture a bowl, the bowl shape when the lip is upwards signifies concavity up. On the other hand, a function is **concave down** if its graph opens downwards, similar to an upside-down bowl. When the function is concave down, this means the slopes of the tangent lines are decreasing. The sign of the second derivative, denoted as \( f''(x) \), determines the concavity:
- If \( f''(x) > 0 \), the function is concave up on that interval.
- If \( f''(x) < 0 \), the function is concave down on that interval.
Second Derivative Test
The Second Derivative Test is a handy tool in calculus used to determine concavity and identify local extrema of differentiable functions. It evaluates the second derivative, \( f''(x) \), at critical points found where the first derivative \( f'(x) = 0 \). These critical points are where potential maxima and minima occur.
The process involves the following steps:
The process involves the following steps:
- Find the critical points by solving \( f'(x) = 0 \).
- Plug these points into \( f''(x) \) to see the sign of the second derivative.
- If \( f''(x) > 0 \) at a critical point, there is a local minimum (function is concave up).
- If \( f''(x) < 0 \) at a critical point, there is a local maximum (function is concave down).
- If \( f''(x) = 0 \), the test is inconclusive, and alternative methods may be needed.
Calculus Education
Calculus is a core subject in mathematics education that involves studying changes and motion through differentiation and integration. One of its crucial elements is the understanding of derivatives, which are used to determine rates of change and slopes of curves.
Effective calculus education involves breaking down fundamental concepts such as derivatives, integrals, limits, and continuity into simple, digestible pieces for easier understanding.
Effective calculus education involves breaking down fundamental concepts such as derivatives, integrals, limits, and continuity into simple, digestible pieces for easier understanding.
- Start with a strong foundation in pre-calculus concepts like functions and algebra.
- Utilize visual aids such as graphs and animations to demonstrate concepts like slope and area under curves.
- Encourage solving practical problems, such as motion and growth models, to see real-world applications of calculus.
- Discuss strategies for understanding complicated concepts like Taylor polynomials, providing step-by-step guidance.
Other exercises in this chapter
Problem 48
explain what is wrong with the statement. $$\begin{aligned} &\text { Using the Taylor series for } e^{x}=1+x+\frac{\pi^{2}}{2 !}+\frac{x^{3}}{3 !}+\cdots\\\ &\t
View solution Problem 48
Explain what is wrong with the statement. The radius of convergence is 2 for the following Taylor series: \(1+(x-3)+(x-3)^{2}+(x-3)^{3}+\cdots\).
View solution Problem 49
give an example of: A function with no Taylor series around 0
View solution Problem 49
Give an example of: A function with a Taylor series whose third-degree term is zero.
View solution