Problem 49
Question
Add or subtract as indicated. $$\frac{3}{2 x+4}+\frac{2}{3 x+6}$$
Step-by-Step Solution
Verified Answer
The result of adding \(\frac{3}{2x+4}\) and \(\frac{2}{3x+6}\) is \(\frac{13}{6x+12}\).
1Step 1: Identify the denominators
The denominators for the two fractions are \(2x+4\) and \(3x+6\).
2Step 2: Finding the common denominator
We need a common denominator to add these two fractions. The lowest common denominator of \(2x+4\) and \(3x+6\) is \(6x+12\) which can be deduced as it is common multiple of both.
3Step 3: Convert to common denominator
Convert each fraction to the equivalent fraction with this common denominator. This is done by multiplying the numerator and denominator of each fraction by the factor that the denominator needs to become the common denominator.\nThe first fraction becomes \(\frac{3}{2x+4} * \frac{3}{3} = \frac{9}{6x+12}\) and the second one becomes \(\frac{2}{3x+6} * \frac{2}{2} = \frac{4}{6x+12}\)
4Step 4: Add the fractions
We can now add these fractions as they have the same denominator: \(\frac{9}{6x+12} + \frac{4}{6x+12} = \frac{9+4}{6x+12}\)
5Step 5: Simplify the result
Simplify the resulting fraction by combining the numerators: \(\frac{13}{6x+12}\)
Other exercises in this chapter
Problem 49
Factor each perfect square trinomial. $$x^{2}+2 x+1$$
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Simplify each exponential expression. $$\frac{8 x^{20}}{2 x^{4}}$$
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Find each product. $$(7-2 x)^{2}$$
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In Exercises \(45-54,\) rationalize the denominator. $$\frac{13}{3+\sqrt{11}}$$
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