Problem 49
Question
A baseball coach is creating a nine-player batting order by selecting from a team of \( 15 \) players. How many different batting orders are possible?
Step-by-Step Solution
Verified Answer
The number of different batting orders possible is \( 15! / 6! \)
1Step 1: Understanding the problem
We're given a total of \( 15 \) players and we need to select \( 9 \) players for a batting order. The fact that the order of players matters makes this a permutation problem. To calculate this we can use the permutation formula \( nPr = n! / (n - r)! \) where \( n = 15 \) (total number of players), and \( r = 9 \) (number of players in the batting order).
2Step 2: Apply the permutation formula
The permutation formula is \( nPr = n! / (n - r)! \). Put \( n = 15 \) and \( r = 9 \) into the permutation formula, we have: \( 15P9 = 15! / (15 - 9)! = 15! / 6! \).
3Step 3: Calculate the factorial
Use the factorial function to calculate \( 15! \) and \( 6! \). The factorial function is a product of an integer and all the integers below it. It's denoted by the exclamation mark, !. So \( 15! = 15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 \) and \( 6! = 6 × 5 × 4 × 3 × 2 × 1 \). The quotient of these two factorials will give the total number of different batting orders possible.
4Step 4: Calculate the number of permutations
The result of \( 15! / 6! \) will give us the number of different permutations possible with \( 15 \) players and a batting order of \( 9 \) players. This way we can find out how many different batting orders are possible.
Key Concepts
Factorials and Their ApplicationCounting Methods and PermutationsCombinatorics and Its Versatility
Factorials and Their Application
In mathematics, the concept of the factorial, represented by an exclamation mark (!), plays a crucial role in several calculations, especially those involving permutations and combinations. A factorial of a non-negative integer, say \( n \), is the product of all positive integers less than or equal to \( n \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). It provides a way to determine the number of ways objects can be arranged in order.
Factorials are key in calculating permutations, which is why they appear in the permutation formula \( nPr = \frac{n!}{(n-r)!} \). Here, the factorial helps to account for arranging a smaller number of items (\( r \)) out of a larger set (\( n \)).
Factorials are key in calculating permutations, which is why they appear in the permutation formula \( nPr = \frac{n!}{(n-r)!} \). Here, the factorial helps to account for arranging a smaller number of items (\( r \)) out of a larger set (\( n \)).
- Factorials grow rapidly: even small numbers when factorialized become very large.
- Mathematically essential: used in various fields, from statistics to economic modeling.
Counting Methods and Permutations
Counting methods are strategies used to determine the number of possible arrangements or selections of objects. One of the most common counting methods in mathematics is permutations.
Permutations are used specifically when the arrangement or order of the objects matters. For example, in a batting order for baseball, each player's position is crucial, making it a permutation problem.
The formula for permutations is \( nPr = \frac{n!}{(n - r)!} \), where:
In our problem, selecting 9 players out of 15 and arranging them in order is a classic example of permutations, as illustrated by the solution.
Permutations are used specifically when the arrangement or order of the objects matters. For example, in a batting order for baseball, each player's position is crucial, making it a permutation problem.
The formula for permutations is \( nPr = \frac{n!}{(n - r)!} \), where:
- \( n \) is the total number of objects.
- \( r \) is the number of objects to arrange.
In our problem, selecting 9 players out of 15 and arranging them in order is a classic example of permutations, as illustrated by the solution.
Combinatorics and Its Versatility
Combinatorics is a fascinating branch of mathematics that deals with counting, arranging, and structuring sets of elements. It comes in handy in solving problems involving permutations and combinations. While permutations focus on the order, combinations focus merely on the selection of items.
Combinatorics offers systematic counting principles, such as the multiplication principle and addition principle, that help simplify complex counting scenarios.
Understanding these concepts enriches our ability to approach and solve a variety of real-world problems through a mathematical lens.
Combinatorics offers systematic counting principles, such as the multiplication principle and addition principle, that help simplify complex counting scenarios.
- Permutations: Important when order matters.
- Combinations: Used when the order does not matter (not directly applied here, but good to know).
Understanding these concepts enriches our ability to approach and solve a variety of real-world problems through a mathematical lens.
Other exercises in this chapter
Problem 48
In Exercises 47-62, write an expression for the apparent \(n\)th term of the sequence. (Assume that \( n \) begins with 1.) \( 3, 7, 11, 15, 19, \dots \)
View solution Problem 49
A college sends a survey to selected members of the class of 2009. Of the 1254 people who graduated that year, 672 are women, of whom 124 went on to graduate sc
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In Exercises 45 - 52, find the specified \( n \)th term in the expansion of the binomial. \( \left(4x + 3y\right)^{9}, \quad n = 8 \)
View solution Problem 49
In Exercises 49 - 58, find the sum using the formulas for the sums of powers of integers. \( \sum_{n=1}^{15}n \)
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