Problem 489
Question
Determine whether Table 4.32 could represent a function that is linear, exponential, or neither. If it appears to be exponential, find a function that passes through the points. $$\begin{array}{|c|c|c|c|c|}\hline x & {1} & {2} & {3} & {4} \\ \hline f(x) & {3} & {0.9} & {0.27} & {0.081} \\ \hline\end{array}$$
Step-by-Step Solution
Verified Answer
The table represents an exponential function: \(f(x) = 3 \cdot (0.3)^{x-1}\).
1Step 1: Identify Linear Change
First, we check if the function is linear by evaluating the change in the y-values. In this case, each y-value change is not constant: \(3-0.9 eq 0.9-0.27\), and so on. Thus, the function is not linear.
2Step 2: Identify Exponential Change
Next, check if the function is exponential by calculating the ratio between consecutive y-values: \( \frac{0.9}{3} = 0.3\), \( \frac{0.27}{0.9} = 0.3\), \( \frac{0.081}{0.27} = 0.3\). Since the ratio is constant, the function is exponential.
3Step 3: Find the Exponential Function
An exponential function has the form \( f(x) = ab^x \). We identify \(a = 3\) from the initial value when \( x=1\), and the constant ratio (base of the exponent) \(b = 0.3\). Thus, the function is \(f(x) = 3 \cdot (0.3)^{x-1}\).
Key Concepts
Linear FunctionsFunction TablesRatio Analysis
Linear Functions
Linear functions are an essential part of mathematics and are commonly used to describe constant change. A linear function can be recognized by its straight-line representation on a graph. A clear indicator of a linear function is that the difference between consecutive outputs, or y-values, remains constant as x increases. This consistent difference is known as the slope.
For example, if we have a dataset where each y-value decreases by 2 as x increases by 1, then such a relationship would be considered linear. In our exercise, the differences between the consecutive y-values are not the same, which clearly indicates that the function is not linear. This is confirmed when you calculate:
For example, if we have a dataset where each y-value decreases by 2 as x increases by 1, then such a relationship would be considered linear. In our exercise, the differences between the consecutive y-values are not the same, which clearly indicates that the function is not linear. This is confirmed when you calculate:
- The change from 3 to 0.9 is -2.1
- The change from 0.9 to 0.27 is -0.63
- The change from 0.27 to 0.081 is -0.189
Function Tables
Function tables are a practical way to organize and analyze relationships between variables. They help in visually checking whether the function behaves linearly, exponentially, or otherwise by listing values of x and the corresponding f(x).
By examining the outputs (f(x)) for changes and patterns, one can deduce the nature of the function. In our example, as x increases, we notice that f(x) does not change linearly, hinting towards an exponential relationship instead. Looking at the table:
By examining the outputs (f(x)) for changes and patterns, one can deduce the nature of the function. In our example, as x increases, we notice that f(x) does not change linearly, hinting towards an exponential relationship instead. Looking at the table:
- For x = 1, f(x) = 3
- For x = 2, f(x) = 0.9
- For x = 3, f(x) = 0.27
- For x = 4, f(x) = 0.081
Ratio Analysis
Ratio analysis is a powerful technique to determine the type of function you are dealing with. When trying to identify an exponential function, examining the ratio of y-values between consecutive points provides a solid clue. Consistent ratios suggest exponential growth or decay.
In the exercise provided, the constant ratio was 0.3, reinforcing the discovery that the function is exponential. Calculating the ratios for each consecutive point:
In the exercise provided, the constant ratio was 0.3, reinforcing the discovery that the function is exponential. Calculating the ratios for each consecutive point:
- From 3 to 0.9, the ratio is \( \frac{0.9}{3} = 0.3 \)
- From 0.9 to 0.27, the ratio is \( \frac{0.27}{0.9} = 0.3 \)
- From 0.27 to 0.081, the ratio is \( \frac{0.081}{0.27} = 0.3 \)
Other exercises in this chapter
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