Problem 481
Question
Recall that the general form of a logistic equation for a population is given by \(P(t)=\frac{c}{1+a e^{-b t}},\) such that the initial population at time \(t=0\) is \(P(0)=P_{0}\) . Show algebraically that \(\frac{c-P(t)}{P(t)}=\frac{c-P_{0}}{P_{0}} e^{-b t}\).
Step-by-Step Solution
Verified Answer
We verified the expression \( \frac{c-P(t)}{P(t)} = \frac{c-P_{0}}{P_{0}} e^{-b t} \) using algebraic manipulations of the logistic equation.
1Step 1: Understand the Logistic Equation
The logistic equation is given by \[ P(t) = \frac{c}{1 + ae^{-bt}} \] Here, \( c \) represents the carrying capacity, \( a \) and \( b \) are positive constants, \( e \) is the base of the natural logarithm, and \( P(t) \) is the population at time \( t \).
2Step 2: Substitute Initial Condition
The initial condition is \( P(0) = P_0 \). Substitute \( t = 0 \) into the logistic equation:\[ P(0) = \frac{c}{1 + a e^{0}} = \frac{c}{1 + a} \]So, \( P_0 = \frac{c}{1 + a} \). Rearrange to find \( a \).
3Step 3: Express 'a' in terms of known variables
Rearrange the equation \( P_0 = \frac{c}{1 + a} \) to solve for \( a \):\[ a = \frac{c - P_0}{P_0} \]
4Step 4: Substitute 'a' back into the Logistic Equation
Use the expression for \( a \) from Step 3 and substitute it into the logistic equation:\[ P(t) = \frac{c}{1 + \frac{c - P_0}{P_0}e^{-bt}} \]Simplify the denominator. It becomes:\[ P(t) = \frac{c}{\frac{P_0 + (c - P_0)e^{-bt}}{P_0}} \]
5Step 5: Simplify the Expression
Simplify the expression:\[ P(t) = \frac{c P_0}{P_0 + (c - P_0)e^{-bt}} \]
6Step 6: Derive the Required Form
We need to show:\[ \frac{c - P(t)}{P(t)} = \frac{c - P_0}{P_0}e^{-bt} \]Substitute \( P(t) = \frac{c P_0}{P_0 + (c - P_0)e^{-bt}} \) into the left side:\[ \frac{c - \frac{c P_0}{P_0 + (c - P_0)e^{-bt}}}{\frac{c P_0}{P_0 + (c - P_0)e^{-bt}}} \]
7Step 7: Simplify Both Numerator and Denominator
The expression becomes:\[ \frac{c(P_0 + (c - P_0)e^{-bt}) - c P_0}{c P_0} \]Which simplifies to:\[ \frac{cP_0 + c(c - P_0)e^{-bt} - cP_0}{cP_0} \]\[ = \frac{c(c - P_0)e^{-bt}}{cP_0} \]
8Step 8: Verify the Final Expression
Cancel \( c \) from numerator and denominator:\[ = \frac{c - P_0}{P_0}e^{-bt} \]This confirms the required form.
Key Concepts
Carrying CapacityNatural LogarithmInitial Population
Carrying Capacity
The term 'carrying capacity' is pivotal in understanding logistic equations in population dynamics. In this context, carrying capacity, denoted as \( c \), refers to the maximum population size that the environment can sustain indefinitely. It represents a balance where resources are available at a rate that can support this maximum population size without depleting resources.
Here are some key points about carrying capacity:
Here are some key points about carrying capacity:
- It is a limit that a population cannot surpass, defined by the environment's resources.
- An increasing population approaches carrying capacity, which slows growth due to resource limitations.
- Once at carrying capacity, the population stabilizes, barring other events like long-term changes in environment or species.
Natural Logarithm
The natural logarithm is an important concept when dealing with exponential functions, such as those found in logistic equations. Its base, \( e \), is approximately equal to 2.718281828, and is a fundamental mathematical constant.
In the logistic equation \( P(t) = \frac{c}{1 + ae^{-bt}} \), the term \( e^{-bt} \) is crucial. Here, \( e^{-bt} \) is an exponential decay factor, which demonstrates how quickly the effect of the initial population decreases over time.
Key aspects of natural logarithms include:
In the logistic equation \( P(t) = \frac{c}{1 + ae^{-bt}} \), the term \( e^{-bt} \) is crucial. Here, \( e^{-bt} \) is an exponential decay factor, which demonstrates how quickly the effect of the initial population decreases over time.
Key aspects of natural logarithms include:
- They are often used to simplify calculations involving exponential growth or decay.
- The function \( e^{x} \) paired with \( \ln(x) \) are inverses, meaning computing the natural log of an exponent retraces steps back to its original number.
- Understanding its properties and manipulation is important to handle expressions such as in the logistic equation’s derivations.
Initial Population
The initial population, denoted by \( P_0 \), is a key parameter in logistic equations that reflects the starting point of population studies. In the context of the equation \( P(t) = \frac{c}{1 + ae^{-bt}} \), it specifies the population size at \( t = 0 \).
Let's break it down:
Let's break it down:
- The expression \( P(0) = P_0 = \frac{c}{1 + a} \) helps establish a baseline, allowing predictions of how populations change over time.
- It directly influences the term \( a \), derived from rearranging \( a = \frac{c - P_0}{P_0} \), where \( a \) affects how quickly the carrying capacity is reached.
- Understanding \( P_0 \) helps inform how initial conditions (like population size, distribution, or environment) affect future dynamics.
Other exercises in this chapter
Problem 479
For the following exercises, refer to Table 4.31. $$\begin{array}{|c|c|c|c|c|c|c|c|c|}\hline x & {0} & {2} & {4} & {5} & {7} & {8} & {10} & {11} & {15} & {17} \
View solution Problem 480
For the following exercises, refer to Table 4.31. $$\begin{array}{|c|c|c|c|c|c|c|c|c|}\hline x & {0} & {2} & {4} & {5} & {7} & {8} & {10} & {11} & {15} & {17} \
View solution Problem 482
Use a graphing utility to find an exponential regression formula \(f(x)\) and a logarithmic regression formula \(g(x)\) for the points \((1.5,1.5)\) and \((8.5,
View solution Problem 484
Find the inverse function \(f^{-1}(x)\) for the logistic function \(f(x)=\frac{c}{1+a e^{-b x}} .\) Show all steps.
View solution