Problem 48
Question
Write the quadratic equation in standard form. Solve using the quadratic formula. $$2 q^{2}-6=-4 q$$
Step-by-Step Solution
Verified Answer
The given equation in standard form is \(2q^2 + 4q + 6 = 0\). However, there are no real solutions as the discriminant is negative.
1Step 1: Writing the equation in standard form
The given equation is \(2q^2 - 6 = -4q\). The standard form of a quadratic equation is \(ax^2 + bx + c = 0\). To convert the given equation into standard form, we'll need to get all terms on one side of the equation: \(2q^2 + 4q + 6 = 0\)
2Step 2: Solving using the Quadratic Formula
The quadratic formula is given by \[x = (-b ± √(b^2 - 4ac)) / (2a)\]. Let's substitute \(a=2\), \(b=4\), and \(c=6\) into the quadratic formula. This gives \[ q = (-4 ± √((4^2) - 4*2*6)) / (2*2) \].
3Step 3: Simplify the Equation
Now we simplify under the square root: \[ q = (-4 ± √(16 - 48)) / 4 \]. Since the number under the square root (known as the discriminant) is negative, this equation has no real solutions.
Key Concepts
Quadratic FormulaStandard FormDiscriminant
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are equations of the second degree. A quadratic equation takes the form of \[ ax^2 + bx + c = 0 \], where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). The quadratic formula helps find the values of \( x \) that satisfy this equation.
The quadratic formula is expressed as: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
- Here, \( b^2 - 4ac \) is termed the discriminant.- The two solutions provided by the formula are due to the "+" and "-" signs, representing the possibility of two values for \( x \).
This formula is essential because it offers a straightforward method to find the roots of any quadratic equation, provided that a mathematical solution exists for the equation.
The quadratic formula is expressed as: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
- Here, \( b^2 - 4ac \) is termed the discriminant.- The two solutions provided by the formula are due to the "+" and "-" signs, representing the possibility of two values for \( x \).
This formula is essential because it offers a straightforward method to find the roots of any quadratic equation, provided that a mathematical solution exists for the equation.
Standard Form
Writing a quadratic equation in standard form is key to easily solving it, especially when using methods like the quadratic formula. The standard form of a quadratic equation is: \[ ax^2 + bx + c = 0 \].
- Here, \( a \), \( b \), and \( c \) are real numbers, where \( a eq 0 \).- This equation is called 'quadratic' because the highest degree term is squared (\( x^2 \)).
To rewrite an equation in standard form, make sure all terms are on one side of the equation and the equation is set to zero. For instance, with \[ 2q^2 - 6 = -4q \], we need to bring all terms to one side:\[ 2q^2 + 4q + 6 = 0 \].Setting it to zero allows us to apply solving techniques like the quadratic formula or factoring, which rely on the equation being in this form.
- Here, \( a \), \( b \), and \( c \) are real numbers, where \( a eq 0 \).- This equation is called 'quadratic' because the highest degree term is squared (\( x^2 \)).
To rewrite an equation in standard form, make sure all terms are on one side of the equation and the equation is set to zero. For instance, with \[ 2q^2 - 6 = -4q \], we need to bring all terms to one side:\[ 2q^2 + 4q + 6 = 0 \].Setting it to zero allows us to apply solving techniques like the quadratic formula or factoring, which rely on the equation being in this form.
Discriminant
The discriminant is a key part of the quadratic formula and plays a crucial role in determining the nature of the solutions of a quadratic equation.
It is represented within the formula as \( b^2 - 4ac \).
- The discriminant helps understand how many real roots a quadratic equation has:
It is represented within the formula as \( b^2 - 4ac \).
- The discriminant helps understand how many real roots a quadratic equation has:
- If \( b^2 - 4ac > 0 \), the quadratic equation has two distinct real solutions.
- If \( b^2 - 4ac = 0 \), there is exactly one real solution, and it is often called a repeated or "double" root.
- If \( b^2 - 4ac < 0 \), the quadratic equation has no real solutions, resulting in complex or imaginary solutions.
Other exercises in this chapter
Problem 48
Use a calculator to evaluate the expression. Round the results to the nearest hundredth. $$\frac{1 \pm 6 \sqrt{8}}{6}$$
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Write an equation of the line that passes through the two points. $$(-3,-9),(5,7)$$
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Use a graphing calculator to approximate the solution of the equation. $$ -8 x^{2}-24 x+32=0 $$
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Graph the equation. $$y=-x^{2}+4 x+1$$
View solution