Problem 48
Question
Write \(\left(\frac{2 s}{2 s+1}-1\right) \div\left(1+\frac{2 s}{1-2 s}\right)\) in simplest form.
Step-by-Step Solution
Verified Answer
\( \frac{-1 + 2s}{2s+1} \)
1Step 1: Simplify the First Fraction
Start with the first part of the expression: \( \frac{2s}{2s+1} - 1 \). To subtract 1, we need a common denominator:\[ \frac{2s}{2s+1} - \frac{2s+1}{2s+1} = \frac{2s - (2s+1)}{2s+1} = \frac{2s - 2s - 1}{2s+1} = \frac{-1}{2s+1}. \]The simplified form of the first fraction is \( \frac{-1}{2s+1} \).
2Step 2: Simplify the Second Fraction
Now, simplify the second part: \( 1 + \frac{2s}{1-2s} \). Find a common denominator:\[ \frac{1(1-2s)}{1-2s} + \frac{2s}{1-2s} = \frac{1 - 2s + 2s}{1-2s} = \frac{1}{1-2s}. \]The second expression becomes \( \frac{1}{1-2s} \).
3Step 3: Divide the Simplified Fractions
You now have two fractions: \( \frac{-1}{2s+1} \) divided by \( \frac{1}{1-2s} \). To divide by a fraction, multiply by its reciprocal:\[ \frac{-1}{2s+1} \times \frac{1-2s}{1} = \frac{-1(1-2s)}{2s+1}. \]This simplifies to:\[ \frac{-1 + 2s}{2s+1}. \]
4Step 4: Final Simplification (If needed)
Inspect the final expression \( \frac{-1 + 2s}{2s+1} \). There are no further simplifications available since the numerator \(-1 + 2s\) and the denominator \(2s+1\) have no common factors. Therefore, the expression is in its simplest form.
Key Concepts
Fraction SimplificationDividing FractionsAlgebraic Expressions
Fraction Simplification
Fraction simplification makes dealing with rational expressions easier and more efficient. The goal of simplifying fractions is to make them as easy to work with as possible.
To simplify a fraction, you need to:
By achieving this, fractions become easier to work with, especially when further operations like division or addition are required.
To simplify a fraction, you need to:
- Find the greatest common factor (GCF) of the numerator and the denominator.
- Divide both the numerator and the denominator by that GCF, effectively reducing the fraction.
By achieving this, fractions become easier to work with, especially when further operations like division or addition are required.
Dividing Fractions
Dividing fractions may initially seem daunting, but it's straightforward once you understand the concept of reciprocals. To divide by a fraction, you multiply by its reciprocal. This is because dividing by a number is the same as multiplying by its multiplicative inverse.
Let's break it down:
Remember, practicing this method helps with understanding, and soon you will divide fractions with confidence!
Let's break it down:
- First, identify the two fractions involved.
- Flip the second fraction (it's now the reciprocal).
- Multiply the first fraction by this reciprocal.
Remember, practicing this method helps with understanding, and soon you will divide fractions with confidence!
Algebraic Expressions
Algebraic expressions like those found in rational functions include variables, constants, and operations. They represent real numbers through calculation and variable manipulation.
Understanding these expressions aids in recognizing relationships between quantities:
Algebraic expressions can seem tricky, but seeing them as grouped elements interacting helps in solving larger mathematical problems efficiently.
Understanding these expressions aids in recognizing relationships between quantities:
- Variables (e.g., \(s\) in our example) represent numbers and enable the expression to change and adapt.
- Constants (e.g., 1, -1 in the expressions) remain unchanged during problem-solving.
- Operations (addition, subtraction, multiplication, division) showcase how these quantities interact.
Algebraic expressions can seem tricky, but seeing them as grouped elements interacting helps in solving larger mathematical problems efficiently.
Other exercises in this chapter
Problem 48
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