Problem 48
Question
Which of the following are correct formulas for ionic compounds? For those that are not, give the correct formula. (a) \(\mathrm{Ca}_{2} \mathrm{O}\) (b) \(\operatorname{SrBr}_{2}\) (c) \(\mathrm{Fe}_{2} \mathrm{O}_{5}\) (d) \(\mathrm{Li}_{2} \mathrm{O}\)
Step-by-Step Solution
Verified Answer
Correct formulas: (a) CaO, (b) SrBr₂, (d) Li₂O; (c) should be Fe₂O₃ or FeO.
1Step 1: Validate calcium oxide formula
The compound \(\text{Ca}_2\text{O}\) suggests a combination of calcium ions \(\text{Ca}^{2+}\) and oxide ions \(\text{O}^{2-}\). One calcium ion combines with one oxide ion because their charges have the same magnitude and opposite signs, neutralizing each other. Thus, the correct formula is \(\text{CaO}\).
2Step 2: Validate strontium bromide formula
The given formula \(\text{SrBr}_2\) consists of strontium ions \(\text{Sr}^{2+}\) and bromide ions \(\text{Br}^-\). Since strontium has a 2+ charge and each bromide ion has a 1- charge, two bromide ions are required to balance one strontium ion, making the formula \(\text{SrBr}_2\) correct.
3Step 3: Validate iron(II) oxide formula
The formula \(\text{Fe}_2\text{O}_5\) is proposed but incorrect because iron forms common ions of \(\text{Fe}^{2+}\) or \(\text{Fe}^{3+}\), while oxide ions are \(\text{O}^{2-}\). To balance 3+ ions, \(\text{Fe}_2\text{O}_3\) is often formed when using iron (III), or \(\text{FeO}\) in case of iron (II) oxide based on 2+ charge.
4Step 4: Validate lithium oxide formula
The compound \(\text{Li}_2\text{O}\) pairs lithium ions \(\text{Li}^+\) with oxide ions \(\text{O}^{2-}\). Two lithium ions balance the 2- charge of one oxide ion. Thus, \(\text{Li}_2\text{O}\) is the correct formula.
Key Concepts
calcium oxidestrontium bromideiron oxidelithium oxide
calcium oxide
Calcium oxide is a simple yet important ionic compound. An ionic bond forms between the calcium ion, Ca\(^{2+}\), and the oxide ion, O\(^{2-}\). Due to their matching charges in magnitude but opposite in sign, only one calcium ion is needed to balance one oxide ion's charge. This results in a neutral compound, adding up to the formula CaO.
- Calcium ions carry a 2+ charge, indicating a loss of two electrons from a neutral calcium atom.
- Oxide ions, on the other hand, carry a 2- charge, formed when an oxygen atom gains two electrons.
strontium bromide
Strontium bromide is another type of ionic compound that forms through the interaction between strontium ions (Sr\(^{2+}\)) and bromide ions (Br\(^-\)). The resulting compound is correctly noted as SrBr\(_2\).
- The strontium ion has a charge of 2+, indicating it loses two electrons.
- Bromide ions each have a 1- charge, gaining one electron to form a stable ion.
iron oxide
Iron oxides can be a bit tricky due to the multiple oxidation states iron can exhibit. Commonly, you might encounter either iron(II) oxide (FeO) or iron(III) oxide (Fe\(_2\)O\(_3\)).
- Iron(II) oxide involves Fe\(^{2+}\) ions combining with O\(^{2-}\) ions. A one-to-one ratio of these ions forms FeO.
- Iron(III) oxide uses Fe\(^{3+}\) ions, requiring two iron ions to balance three oxide ions. This results in the compound Fe\(_2\)O\(_3\).
lithium oxide
Lithium oxide showcases a more straightforward ionic compound formation. It involves lithium ions, Li\(^+\), bonding with oxide ions, O\(^{2-}\). To achieve charge neutrality in lithium oxide, two Li\(^+\) ions are needed to balance the charge of one O\(^{2-}\) ion, leading to the formula Li\(_2\)O.
- Lithium ions are derived from lithium atoms that have lost one electron each, resulting in a 1+ charge for each ion.
- The oxide ion has a 2- charge, needing two positively charged lithium ions to fully neutralize it.
Other exercises in this chapter
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