Problem 48
Question
Verify the identity. $$ \cos ^{2} x-\sin ^{2} x=2 \cos ^{2} x-1 $$
Step-by-Step Solution
Verified Answer
The identity is verified; both sides equal \( 2\cos^2 x - 1 \).
1Step 1: Recall the Pythagorean Identity
The Pythagorean identity states that \( \cos^2 x + \sin^2 x = 1 \). This is fundamental in verifying trigonometric identities.
2Step 2: Rewrite the Left Side of the Equation
We start with the left side of the equation: \( \cos^2 x - \sin^2 x \). Use the Pythagorean identity to express \( \sin^2 x \) as \( 1 - \cos^2 x \). Substitute this into the equation to get \( \cos^2 x - (1 - \cos^2 x) \).
3Step 3: Simplify the Expression
Simplify \( \cos^2 x - 1 + \cos^2 x \) by combining like terms. This results in \( 2 \cos^2 x - 1 \).
4Step 4: Compare the Simplified Expression with the Right Side
Now, compare the simplified expression \( 2 \cos^2 x - 1 \) with the right side of the original equation \( 2 \cos^2 x - 1 \). They are identical, thus verifying the identity.
Key Concepts
Pythagorean identitycosine functionsine function
Pythagorean identity
The Pythagorean identity is one of the fundamental identities in trigonometry. It is expressed as \(\cos^2 x + \sin^2 x = 1\). This identity is derived from the Pythagorean theorem and is valid for any angle \(x\). It's named after the Greek mathematician Pythagoras because of its connection to the Pythagorean Theorem. This identity allows you to express one trigonometric function in terms of another.
For instance:
For instance:
- You can write \(\sin^2 x = 1 - \cos^2 x\).
- Similarly, \(\cos^2 x = 1 - \sin^2 x\).
cosine function
The cosine function, \(\cos x\), is a crucial component of trigonometry. It represents the ratio of the adjacent side to the hypotenuse in a right-angled triangle for an angle \(x\). Cosine is periodic with a period of \(2\pi\), meaning its values repeat every \(2\pi\) radians. The values of the cosine function can range from -1 to 1.
Understanding \(\cos x\) can be visualized on the unit circle:
Understanding \(\cos x\) can be visualized on the unit circle:
- In the unit circle, the \(x\)-coordinate of a point gives the value of \(\cos x\).
- The function starts from 1 at \(x = 0\).
- It decreases to 0 at \(x = \pi/2\), then to -1 at \(x = \pi\).
- It continues this symmetrical pattern.
sine function
The sine function, \(\sin x\), is another primary function in trigonometry. It describes the ratio of the opposite side to the hypotenuse in a right-angled triangle. Like cosine, sine is periodic with a period of \(2\pi\). The function oscillates between -1 and 1 across this interval.
Visualize the sine function on the unit circle:
Visualize the sine function on the unit circle:
- The \(y\)-coordinate of a point on the circle gives the value of \(\sin x\).
- \(\sin x\) starts from 0 at \(x = 0\).
- It reaches 1 at \(x = \pi/2\), and returns to 0 at \(x = \pi\).
- This pattern mirrors that of cosine but is phase-shifted.
Other exercises in this chapter
Problem 47
Show that if \(\beta-\alpha=\pi / 2\) , then $$ \sin (x+\alpha)+\cos (x+\beta)=0 $$
View solution Problem 47
47–52 Write the sum as a product. $$\sin 5 x+\sin 3 x$$
View solution Problem 48
Rewrite the expression as an algebraic expression in \(x .\) \(\sin \left(\tan ^{-1} x-\sin ^{-1} x\right)\)
View solution Problem 48
Find all solutions of the equation in the interval \([0,2 \pi).\) $$3 \sec ^{2} x+4 \cos ^{2} x=7$$
View solution