Problem 48
Question
Use the discriminant to determine the number and types of solutions of each equation. $$ 5-4 x+12 x^{2}=0 $$
Step-by-Step Solution
Verified Answer
The equation has two complex solutions, as the discriminant is negative.
1Step 1: Write the equation in standard form
The given equation is:\[ 5 - 4x + 12x^2 = 0 \]We rewrite it in standard quadratic form as:\[ 12x^2 - 4x + 5 = 0 \]Here, the standard form is \( ax^2 + bx + c = 0 \) with \( a = 12 \), \( b = -4 \), and \( c = 5 \).
2Step 2: Calculate the discriminant
The discriminant of a quadratic equation \( ax^2 + bx + c = 0 \) is given by:\[ \Delta = b^2 - 4ac \]Substituting the values \( a = 12 \), \( b = -4 \), and \( c = 5 \):\[ \Delta = (-4)^2 - 4 \times 12 \times 5 \]\[ \Delta = 16 - 240 \]\[ \Delta = -224 \]
3Step 3: Interpret the discriminant
The discriminant \( \Delta = -224 \) is negative. A negative discriminant indicates that the quadratic equation has two complex solutions (conjugate pairs), and they are not real.
Key Concepts
Quadratic EquationComplex SolutionsStandard Form
Quadratic Equation
A quadratic equation is a type of polynomial equation that takes the form \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) are constants, and the term \( x \) represents the unknown variable. Quadratic equations are unique because they have a degree of 2, meaning the highest exponent of \( x \) is 2. This degree is what typically results in the characteristic parabolic shape when graphed.
Quadratic equations can have different types of solutions:
These solutions can help us understand the behavior of the quadratic equation in terms of roots and graph intersections with the x-axis.
Quadratic equations can have different types of solutions:
- Real and distinct solutions
- Real and identical solutions (repeated roots)
- Complex (non-real) solutions
These solutions can help us understand the behavior of the quadratic equation in terms of roots and graph intersections with the x-axis.
Complex Solutions
Complex solutions arise in the context of quadratic equations when the discriminant is negative. The discriminant, represented by \( \Delta = b^2 - 4ac \), helps us determine the nature of the roots without actually solving the equation.
When \( \Delta < 0 \), the quadratic equation does not have any real solutions but instead has complex solutions, which occur in the form of conjugate pairs. A complex solution typically appears as:
When \( \Delta < 0 \), the quadratic equation does not have any real solutions but instead has complex solutions, which occur in the form of conjugate pairs. A complex solution typically appears as:
- \( x = \frac{-b + i \sqrt{\left| \Delta \right|}}{2a} \)
- \( x = \frac{-b - i \sqrt{\left| \Delta \right|}}{2a} \)
Standard Form
The standard form of a quadratic equation is expressed as \( ax^2 + bx + c = 0 \). Converting an equation into this form is crucial for solving and analyzing it. In this structure, \( a \) cannot be zero because if it were, the equation would not be quadratic but linear instead.
An easy step-by-step conversion process involves collecting all terms on one side of the equation so that only zero remains on the other. Then arrange the terms by descending powers of \( x \).
This form is not only practical for solving through the quadratic formula but essential for identifying the discriminant, which clarifies the number and type of solutions.
An easy step-by-step conversion process involves collecting all terms on one side of the equation so that only zero remains on the other. Then arrange the terms by descending powers of \( x \).
- Identify coefficients \( a \), \( b \), and \( c \)
- Check if the equation is properly arranged according to powers of \( x \)
- If needed, rearrange terms to fit \( ax^2 + bx + c = 0 \)
This form is not only practical for solving through the quadratic formula but essential for identifying the discriminant, which clarifies the number and type of solutions.
Other exercises in this chapter
Problem 47
Write the equation of the parabola that has the same shape as \(f(x)=5 x^{2}\) but with the given vertex. Call each function \(g(x) .\) $$ (2,3) $$
View solution Problem 47
Without calculating, tell whether each graph has a minimum value or a maximum value. See the Concept Check in the section. $$ f(x)=2 x^{2}-5 $$
View solution Problem 48
Solve each inequality. Write the solution set in interval notation. $$ \frac{4 x}{x-3} \geq 5 $$
View solution Problem 48
Without calculating, tell whether each graph has a minimum value or a maximum value. See the Concept Check in the section. $$ g(x)=-7 x^{2}+x+1 $$
View solution