Problem 48
Question
Use a symbolic differentiation utility to find the derivative of the function. Graph the function and its derivative in the same viewing window. Describe the behavior of the function when the derivative is zero. $$ f(x)=\sqrt{\frac{2 x}{x+1}} $$
Step-by-Step Solution
Verified Answer
The derivative of the function \( f(x)=\sqrt{\frac{2 x}{x+1}} \) is \( f'(x)=\frac{1}{(x+1) \sqrt{\frac{2 x}{x+1}}} \). When the derivative is zero, the function is likely at a maximum, minimum or saddle point.
1Step 1: Differentiate the Given Function
The function is \( f(x)=\sqrt{\frac{2 x}{x+1}} \). With a small rearrangement we can express it as \( f(x)=(2 x/(x+1))^{1/2} \). Now, we can use the chain rule and power rule to find the derivative. The derivative is \( f'(x)=\frac{1}{2}(2 x/(x+1))^{-1/2} * \frac{d}{dx}(2 x/(x+1)) \). Then, \( f'(x)=\frac{1}{2}(2 x/(x+1))^{-1/2} * (2(x+1) - 2x) / (x+1)^2 = \frac{x+1- x}{(x+1) (2x/(x+1))^{1/2}} \), so \( f'(x)=\frac{1}{(x+1) \sqrt{\frac{2 x}{x+1}}} \).
2Step 2: Graph the Function and its Derivative
Both the function \( f(x) \) and its derivative \( f'(x) \) should be graphed in the same viewing window. Note the points where the derivative equals zero or undefined.
3Step 3: Analyze the Behavior of the Function when the Derivative is Zero
When the derivative is zero, it implies that the function is at either a maximum, minimum, or saddle point. Looking at the graph, locate the points where the derivative is zero and observe the behavior of the function at these points.
Other exercises in this chapter
Problem 47
Find an equation of the line that is tangent to the graph of \(f\) and parallel to the given line. $$ f(x)=-\frac{1}{4} x^{2} \quad x+y=0 $$
View solution Problem 47
find the limit $$ \lim _{x \rightarrow-2} \frac{x^{3}+8}{x+2} $$
View solution Problem 48
Find the point(s), if any, at which the graph of \(f\) has a horizontal tangent. $$ f(x)=\frac{x^{2}}{x^{2}+1} $$
View solution Problem 48
find \(f^{\prime}(x)\). $$ f(x)=x^{1 / 3}-1 $$
View solution