Problem 48
Question
The mass of a muon is 207 times the clectron mass; the average lifetime of muons at rest is \(2.20 \mu \mathrm{s}\). In a certain experiment, muons moving through a laboratory are measured to have an average lifetime of \(6.90 \mu \mathrm{s}\). For the moving muons, what are (a) \(\beta, (\) b) \(K,\) and \((c) p(\) in \(\mathrm{MeV} / c) ?\)
Step-by-Step Solution
Verified Answer
(a) \(\beta \approx 0.948\), (b) \(K \approx 228.16\, \mathrm{MeV}\), (c) \(p \approx 317.33\, \mathrm{MeV}/c\)."
1Step 1: Understanding the Problem
We are given the rest lifetime of muons, the moving lifetime, and need to find the velocity (\(\beta\)), kinetic energy (\(K\)), and momentum (\(p)\) of the moving muons. We use the time dilation formula and relativistic equations for energy and momentum.
2Step 1: Calculate Velocity (Beta)
Using time dilation: \[ t' = \frac{t}{\sqrt{1-\beta^2}} \] where \(t = 2.20 \mu s\) (rest lifetime) and \(t' = 6.90 \mu s\) (moving lifetime). Solving for \(\beta\): \[ 6.90 = \frac{2.20}{\sqrt{1-\beta^2}} \] \[ \sqrt{1-\beta^2} = \frac{2.20}{6.90} \] \[ 1-\beta^2 = \left(\frac{2.20}{6.90}\right)^2 \] \[ \beta^2 = 1 - \left(\frac{2.20}{6.90}\right)^2 \] \[ \beta \approx \sqrt{0.8989} \approx 0.948 \]
3Step 2: Calculate Kinetic Energy (K)
The relativistic kinetic energy is \[ K = (\gamma - 1)mc^2 \]. To find \(\gamma\): \[ \gamma = \frac{1}{\sqrt{1 - \beta^2}} \approx \frac{1}{0.3162} \approx 3.16 \]. The muon mass \(m = 207m_e\). \(mc^2 = 207 \times 0.511 \mathrm{MeV} = 105.777 \mathrm{MeV}\). Thus, \[ K = (3.16 - 1) \times 105.777 = 228.16 \mathrm{MeV} \].
4Step 3: Calculate Momentum (p)
The relativistic momentum is \[ p = \gamma mv \] and since \( v = \beta c \), \[ p = \gamma m \beta c \]. With \(\beta = 0.948\) and \(\gamma = 3.16\), \[ p = 3.16 \times 207m_e \times 0.948c = (3.16 \times 0.948) \times 105.777 \mathrm{MeV}/c \]. Simplifying, \[ p \approx 3.00 \times 105.777 \approx 317.33 \mathrm{MeV}/c \].
Key Concepts
Time DilationRelativistic Kinetic EnergyRelativistic MomentumMuon Lifetime
Time Dilation
In the realm of relativity in physics, time dilation is a fascinating phenomenon, emphasizing how time can differ for observers in various frames of motion. Essentially, it suggests that time ticks differently depending on how fast you are moving relative to another observer. In the context of muons in our original exercise, these particles exist at such high speeds that relativistic effects like time dilation become significant.
When muons are at rest, they have a specific lifetime, noted here as 2.20 microseconds. However, when racing through a laboratory with high speeds, observers measure a considerably longer lifetime of 6.90 microseconds. This phenomenon is explained by the time dilation formula:
When muons are at rest, they have a specific lifetime, noted here as 2.20 microseconds. However, when racing through a laboratory with high speeds, observers measure a considerably longer lifetime of 6.90 microseconds. This phenomenon is explained by the time dilation formula:
- \[ t' = \frac{t}{\sqrt{1-\beta^2}} \]
- \( t' \) is the observed time duration (6.90 microseconds)
- \( t \) is the proper time or rest time (2.20 microseconds)
- \( \beta \) is the velocity factor as a fraction of the speed of light \(c\).
Relativistic Kinetic Energy
When objects move at speeds approaching that of light, traditional notions of kinetic energy change, giving rise to what we call relativistic kinetic energy. This form of kinetic energy accounts for the effects of relativity, being crucial for particles like muons traveling near the speed of light. Using the formula:
- \[ K = (\gamma - 1)mc^2 \]
- \( K \) is the relativistic kinetic energy.
- \( \gamma \) (gamma) represents the Lorentz factor, given by \( \frac{1}{\sqrt{1 - \beta^2}} \).
- \( m \) is the rest mass of the particle.
- \( c \) is the speed of light.
Relativistic Momentum
Beyond kinetic energy, particles like muons also exhibit relativistic momentum when approaching light speed, differing from classical momentum understanding. Relativistic momentum is expressed as:
In the researched scenario, the outcome indicates a significantly shifted momentum value of the muon, affirming how its velocity contributes dramatically to the overall momentum.
- \[ p = \gamma m v \]
- \( p \) is the relativistic momentum.
- \( \gamma \) is the Lorentz factor, previously determined.
- \( m \) is the rest mass of the particle (in our case, for muons).
- \( v \) is its velocity, represented as \( \beta c \), where \( \beta \) is the velocity as a fraction of the speed of light.
In the researched scenario, the outcome indicates a significantly shifted momentum value of the muon, affirming how its velocity contributes dramatically to the overall momentum.
Muon Lifetime
Muons, subatomic particles with a charge similar to electrons, are known for their incredibly short lifetimes. At rest, they last approximately 2.20 microseconds, but when moving at high velocities, such as near the speed of light, they exhibit extended lifetimes due to relativistic effects, notable in scientific experiments.
The extended lifetime of moving muons is directly linked to time dilation. As they fly through experimental setups at relativistic speeds, their lifespan stretches from what is measured in the stationary frame. Consequently, observers measure their lifetime as 6.90 microseconds, three times more than their rest lifetime.
Muon lifetime is critical in experimental physics, helping researchers confirm predictions of relativity and observe how time dilation works in real-world scenarios. These experiments provide insights, not just into how fundamental particles behave but also into verifying Einstein's theory, offering tangible evidence of time distortion under high velocity conditions.
Muon lifetime is critical in experimental physics, helping researchers confirm predictions of relativity and observe how time dilation works in real-world scenarios. These experiments provide insights, not just into how fundamental particles behave but also into verifying Einstein's theory, offering tangible evidence of time distortion under high velocity conditions.
Other exercises in this chapter
Problem 46
Suppose that you release a small ball from rest at a depth of \(0.600 \mathrm{~m}\) below the surface in a pool of water. If the density of the ball is 0.300 th
View solution Problem 47
A 5.00 -grain aspirin tablet has a mass of \(320 \mathrm{mg}\). Forhow many kilometers would the encrgy cquivalent of this mass power an automobile? Assume \(12
View solution Problem 49
Canal effect. Figure \(14-45\) shows an anchored barge that cxtcnds across a canal by distance \(d=30 \mathrm{~m}\) and into the water by distance \(b=12 \mathr
View solution Problem 50
To four significant figures, find the following when the kinetic energy is \(10.00 \mathrm{MeV}:\) (a) \(\gamma\) and \((\mathrm{b}) \beta\) for an clectron \(\
View solution