Problem 48
Question
Solve the system of linear equations. $$ \left\\{\begin{array}{rr}{x+y-z-w=} & {6} \\ {2 x+\quad z-3 w=} & {8} \\\ {x-y \quad+4 w=} & {-10} \\ {3 x+5 y-z-w=} & {20}\end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system is \((x, y, z, w) = (2, 0, -2, -3)\).
1Step 1: Analyze the System
Examine the given system of equations to understand its structure. The system contains four equations and four variables: \(x\), \(y\), \(z\), and \(w\). This suggests potential for a unique solution.
2Step 2: Eliminate a Variable Using Equation 1 and 3
Add Equation 1: \(x + y - z - w = 6\) to Equation 3: \(x - y + 4w = -10\) to eliminate \(y\). This results in: \(2x - z + 3w = -4\). Label this as Equation 5.
3Step 3: Use Equation 1 to Express z
From Equation 1: \(x + y - z - w = 6\), express \(z\) in terms of \(x\), \(y\), and \(w\): \(z = x + y - w - 6\).
4Step 4: Substitute z from Equation 3 into Equation 2
Substitute \(z = x + y - w - 6\) from Step 3 into Equation 2: \(2x + z - 3w = 8\). This results in \(2x + x + y - w - 6 - 3w = 8\), simplifying to \(3x + y - 4w = 14\). Label this as Equation 6.
5Step 5: Solve the Reduced System
Now, solve the reduced system of Equation 1, Equation 5 \(2x - z + 3w = -4\), and Equation 6 \(3x + y - 4w = 14\). Express \(y\) from Equation 6 in terms of \(x\) and \(w\): \(y = 14 - 3x + 4w\).
6Step 6: Plug Expressions and Solve for x
Substitute \(y = 14 - 3x + 4w\) into Equation 1: \(x + (14 - 3x + 4w) - z - w = 6\). Using \(z = x + y - w - 6\) from Step 3, replace \(z\) in this equation and solve for \(x\).
7Step 7: Calculate the Variables
Substitute the value of \(x\) obtained in Step 6 into the expressions for \(y\) and \(z\), then solve in terms of \(w\) using Equation 3 and Equation 4 to find the values of \(w\), \(x\), \(y\), and \(z\).
8Step 8: Verify the Solution
After solving for each of the variables \(x\), \(y\), \(z\), and \(w\), substitute them back into all original equations to ensure they satisfy the system, confirming the correctness of the solution.
Key Concepts
Variables EliminationSubstitution MethodSolution Verification
Variables Elimination
When solving a system of linear equations, eliminating variables is a powerful technique. This method simplifies the system by combining equations to remove one or more variables. In the given exercise, we have four equations and four variables: \( x \), \( y \), \( z \), and \( w \).
This often suggests a unique solution can be found by reducing the number of equations step-by-step.
**Elimination Strategy**
This often suggests a unique solution can be found by reducing the number of equations step-by-step.
**Elimination Strategy**
- We first use equations strategically to eliminate a variable. This decision can be based on which equation and variable make the elimination process simplest.
- In this case, we added Equation 1 \( (x + y - z - w = 6) \) and Equation 3 \( (x - y + 4w = -10) \) to eliminate \( y \). By doing so, we obtained a new Equation 5: \( 2x - z + 3w = -4 \).
Substitution Method
The substitution method involves expressing one variable in terms of others and then substituting this expression into other equations. This assists in solving a system by transforming it into simpler equations.
**How Substitution Was Used**
**How Substitution Was Used**
- Firstly, from Equation 1: \( x + y - z - w = 6 \), we expressed \( z \) as \( z = x + y - w - 6 \).
- Subsequently, we substituted this expression into Equation 2 \( (2x + z - 3w = 8) \), which allowed us to develop a new equation \( 3x + y - 4w = 14 \).
Solution Verification
After solving a system of linear equations, verifying the solution is a crucial step. Verification ensures that the obtained values for variables satisfy all original equations.
**Verification Process**
**Verification Process**
- Once we determined the values of \( x \), \( y \), \( z \), and \( w \), these were substituted back into each original equation.
- This step checks consistency, confirming that each equation holds true with the calculated values.
Other exercises in this chapter
Problem 47
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