Problem 48
Question
Solve each problem involving consecutive integers. Find three consecutive even integers such that the sum of the least integer and the greatest integer is 12 more than the middle integer.
Step-by-Step Solution
Verified Answer
The three consecutive even integers are 10, 12, and 14.
1Step 1 - Define the integers
Let the three consecutive even integers be represented by: Let the first even integer be x. The second consecutive even integer will then be x+2. The third consecutive even integer will be x+4.
2Step 2 - Set up the equation
The problem states that the sum of the least integer and the greatest integer is 12 more than the middle integer. Set up an equation based on this information: x + (x+4) = (x+2) + 12.
3Step 3 - Simplify and solve the equation
Combine like terms and solve for x: x + (x+4) = (x+2) + 12 2x + 4 = x + 14 Subtract x from both sides: x + 4 = 14 Subtract 4 from both sides: x = 10.
4Step 4 - Find all integers
Using the value of x, find the three consecutive even integers: The first even integer is 10. The second even integer is 10 + 2 = 12. The third even integer is 10 + 4 = 14.
5Step 5 - Verify the solution
Verify if the integer values satisfy the condition given in the problem: The sum of the first and the third integers is 10 + 14 = 24. The middle integer is 12, and 12 more than the middle integer is 12 + 12 = 24. Since both sums are equal, the integers (10, 12, 14) are the correct solution.
Key Concepts
even integersalgebraic equationssolving equationsinteger propertiesproblem-solving strategies
even integers
Even integers are numbers that are divisible by 2. They include numbers like 2, 4, 6, 8, and so on. To find consecutive even integers, you add 2 to the previous even integer. For example, after 2 comes 4, then 6, and so forth. In our problem, we defined the integers as follows:
- The first even integer is denoted as x.
- The next even integer is x + 2.
- The next even integer is x + 4.
algebraic equations
Algebraic equations involve numbers and variables combined using mathematical operations. In this problem, we set up an equation to relate the even integers. The equation given was: \[ x + (x+4) = (x+2) + 12\]
Here, each term represents either an integer or a combination of integers. Setting up and simplifying algebraic equations helps you find unknown values, which is the goal of this problem.
Here, each term represents either an integer or a combination of integers. Setting up and simplifying algebraic equations helps you find unknown values, which is the goal of this problem.
solving equations
Solving equations involves finding the value of unknowns that make the equation true. In our problem, we solved for x:
- Combine like terms: \( x + (x+4) = (x+2) + 12 \) turns into \( 2x + 4 = x + 14 \)
- Isolate the variable: Subtract x from both sides to get \( x + 4 = 14 \).
- Simplify: Subtract 4 from both sides to find \( x = 10 \).
integer properties
Integers are whole numbers that can be positive, negative, or zero. Even integers are a subset of integers. They have properties that make solving problems straightforward:
- Consecutive integers follow a set pattern.
- Adding or subtracting integers retains another integer (e.g., 2 + 2 = 4).
problem-solving strategies
Effective problem-solving strategies help you find solutions systematically. In this problem, we used the following strategies:
- Define variables: We represented the integers as x, x+2, and x+4.
- Set up equations: Based on the problem statement, we formulated an equation.
- Simplify: We combined like terms and solved for x.
- Verify: After finding the integers, we checked our solution to ensure it met all conditions.
Other exercises in this chapter
Problem 48
Solve each equation, and check the solution. If applicable, tell whether the equation is an identity or a contradiction. \(4(x+2)-8 x-5=-3 x+9-2(x+6)\)
View solution Problem 48
Express each set in simplest interval form. (Hint: Graph each set and look for the intersection or union.) $$ [-1, \infty) \cap(-\infty, 9] $$
View solution Problem 49
Solve each percent problem. Why is it impossible to mix candy worth \(\$ 4\) per \(1 \mathrm{~b}\) and candy worth \(\$ 5\) per Ib to obtain a final mixture wor
View solution Problem 49
12 is what percent of \(48 ?\)
View solution