Problem 48
Question
Solve each equation. See Example \(6 .\) $$ \log \frac{1}{5} x=-3 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = 0.005 \).
1Step 1: Understand the Equation
We are given the logarithmic equation \( \log \frac{1}{5}x = -3 \). This means the logarithm of the expression \( \frac{1}{5}x \) is equal to \(-3\).
2Step 2: Convert Logarithmic Equation to Exponential Form
The expression \( \log \frac{1}{5}x = -3 \) means \( \frac{1}{5}x = 10^{-3} \), by the definition of a logarithm: \( \log_b a = c \) means \( a = b^c \).
3Step 3: Solve for \( x \)
Now, we solve the exponential equation \( \frac{1}{5}x = 10^{-3} \). Multiply both sides by 5 to isolate \( x \): \[ x = 5 \times 10^{-3} \] Calculate the right-hand side: \[ x = 0.005 \]
4Step 4: Verify the Solution
Substitute \( x = 0.005 \) back into the original equation to check: \[ \log \frac{1}{5}(0.005) = \log 0.001 = -3 \]. The solution satisfies the original equation, confirming that \( x = 0.005 \) is correct.
Key Concepts
Exponential EquationsLogarithmic FunctionsSolving Equations
Exponential Equations
Exponential equations are equations where variables appear in exponents. They're foundational in mathematics because they depict constant growth or decay patterns, often observed in nature and finance.
To understand these equations, consider the general form:
To understand these equations, consider the general form:
- General Form: If you have an equation in the form of \( a = b^x \), where \( b \) is a constant base and \( x \) is an exponent, then you're dealing with an exponential equation.
- Utility: Exponential equations are used to model situations like population growth, radioactive decay, and compound interest, where something grows or shrinks at a rate proportional to its current value.
- Solving Tips: Transforming an exponential equation into a simpler form can often involve using logarithms to "bring down" the exponent. This is key in making the variable accessible for solving.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions. They are crucial in algebra because they allow you to solve complex equations by converting them to a simpler form.
Here's a deeper dive into the essence of logarithmic functions:
Here's a deeper dive into the essence of logarithmic functions:
- Definition: The logarithm of a number is the exponent to which the base must be raised to produce that number. For example, in the equation \( \,\log_b a = c \, \), it translates to \( \, b^c = a \, \).
- Properties: There are vital properties of logarithms that make them useful, such as the product rule, the quotient rule, and the power rule. These properties help in manipulating logarithmic expressions effectively.
- Applications: Logarithms are widely used in scientific calculations, such as measuring the intensity of earthquakes on the Richter scale, sound intensity in decibels, and in fields like finance and information theory.
Solving Equations
Solving equations involves finding the variable value that makes the equation true. It's a core concept in mathematics, as it allows us to solve real-world problems by modeling them with mathematical expressions.
Here’s how to efficiently approach solving logarithmic and exponential equations:
Here’s how to efficiently approach solving logarithmic and exponential equations:
- Identify the Type: Recognize if you're dealing with exponential or logarithmic equations. This helps in choosing the appropriate method to solve them.
- Convert and Simplify: Logarithmic equations can often be transformed into exponential equations. This conversion uses the property \( \log_b a = c \Rightarrow a = b^c \), greatly simplifying the process.
- Check Your Work: Always substitute your solution back into the original equation to verify its correctness. This step ensures that no computational errors were made and the solution is accurate.
- Practical Application: Whether you're analyzing population trends, or calculating financial growth, being proficient in solving equations expands your analytical toolkit.
Other exercises in this chapter
Problem 47
Each of the following functions is one-to-one. Find the inverse of each function and express it using \(f^{-1}(x)\) notation. \(f(x)=\sqrt[3]{x}\)
View solution Problem 47
Write logarithm as the sum and/or difference of logarithms of a single quantity. Then simplify, if possible. \(\ln \frac{e x y}{z}\)
View solution Problem 48
Evaluate each expression without using a calculator. $$ \ln \sqrt[5]{e} $$
View solution Problem 48
Discharging a Battery. The charge remaining in a battery decreases as the battery discharges. The charge \(C\) (in coulombs) after \(t\) days is given by the fu
View solution