Problem 48
Question
Simplify. $$ 2^{3}+2^{4}-5\left[8-4(9-10)^{2}\right] $$
Step-by-Step Solution
Verified Answer
4
1Step 1 - Simplify the Exponential Terms
Compute the exponentials: \[ 2^3 = 8 \] and \[ 2^4 = 16 \]. So the expression becomes: \[ 8 + 16 - 5\big[8 - 4(9 - 10)^2\big] \]
2Step 2 - Simplify Inside the Parentheses
Compute the expression inside the innermost parentheses: \[ 9 - 10 = -1 \]. Next, square the result: \[ (-1)^2 = 1 \]. The expression now becomes: \[ 8 + 16 - 5\big[8 - 4 \times 1\big] \]
3Step 3 - Multiply Inside the Brackets
Multiply 4 by the squared result: \[ 4 \times 1 = 4 \]. The expression becomes: \[ 8 + 16 - 5\big[8 - 4\big] \]
4Step 4 - Simplify Inside the Brackets
Subtract inside the brackets: \[ 8 - 4 = 4 \]. The expression is now: \[ 8 + 16 - 5 \times 4 \]
5Step 5 - Multiply
Multiply 5 and 4: \[ 5 \times 4 = 20 \]. The expression now is: \[ 8 + 16 - 20 \]
6Step 6 - Add and Subtract
Finally, add and subtract in order: \[ 8 + 16 = 24 \], then \[ 24 - 20 = 4 \]
Key Concepts
Exponential TermsOrder of OperationsParentheses and Brackets
Exponential Terms
Exponential terms involve numbers raised to a power, such as \(2^3\) and \(2^4\) in the given problem. Here, the base (2) is multiplied by itself as many times as the exponent dictates. For example, \(2^3\) means multiplying 2 by itself 3 times (2 x 2 x 2 = 8). Similarly, \(2^4\) means multiplying 2 by itself 4 times (2 x 2 x 2 x 2 = 16). These calculations are the first step in simplifying the expression.
By computing the exponential terms first, we reduce the complexity of the expression early on. So, our given expression simplifies from: \(2^3 + 2^4\) to 8 + 16, making the overall expression easier to handle. This emphasizes how handling exponentials first can simplify problem-solving in algebraic expressions.
By computing the exponential terms first, we reduce the complexity of the expression early on. So, our given expression simplifies from: \(2^3 + 2^4\) to 8 + 16, making the overall expression easier to handle. This emphasizes how handling exponentials first can simplify problem-solving in algebraic expressions.
Order of Operations
The order of operations is a set of rules to ensure consistent results when simplifying mathematical expressions. Remembering the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)) can help:
Skipping or rearranging these steps can lead to incorrect results. Always follow PEMDAS to make sure expressions simplify correctly.
- **P**arentheses first
- **E**xponents (like \(2^3\) and \(2^4\))
- **MD** (Multiplication and Division from left to right)
- **AS** (Addition and Subtraction from left to right)
Skipping or rearranging these steps can lead to incorrect results. Always follow PEMDAS to make sure expressions simplify correctly.
Parentheses and Brackets
Parentheses and brackets are used to group parts of mathematical expressions that should be handled first. In our problem, parentheses appear inside the brackets. Start with the innermost parentheses, then work outward.
Here, evaluate \((9 - 10)\) first, resulting in -1. This value is then squared. By following the sequence (Parentheses and Brackets), each step becomes manageable, making the overall expression: \(8 + 16 - 5[8 - 4 \times 1]\). Next, handle the multiplication within the brackets to update to: \(8 + 16 - 5[4]\), finally simplifying it.
Using parentheses and brackets effectively clarifies the order in complex expressions, guiding each step toward the correct solution.
Here, evaluate \((9 - 10)\) first, resulting in -1. This value is then squared. By following the sequence (Parentheses and Brackets), each step becomes manageable, making the overall expression: \(8 + 16 - 5[8 - 4 \times 1]\). Next, handle the multiplication within the brackets to update to: \(8 + 16 - 5[4]\), finally simplifying it.
Using parentheses and brackets effectively clarifies the order in complex expressions, guiding each step toward the correct solution.
Other exercises in this chapter
Problem 47
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Add. Do not use the number line except as a check. \(\frac{-2}{7}+\frac{3}{7}\)
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