Problem 48
Question
In an adiabatic flow of a perfect gas in a constantarea duct with friction, we have the inlet condition as \(M_{1}=\) \(2.0, p_{1}=25 \mathrm{kPa}, T_{1}=250 \mathrm{~K}\). The duct length-to-(hydraulic) diameter ratio is \(L D_{h}=10.262\) and the average friction coefficient at the wall is \(C_{f}=0.005\). Assuming gas properties are \(\gamma=1.4\) and \(R=287 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), calculate (a) exit Mach number, \(M_{2}\) (b) total temperature of the gas at the exit, \(T_{12}\) in \(\mathrm{K}\) (c) total pressure of the gas at the exit, \(p_{12}\) in \(\mathrm{kPa}\)
Step-by-Step Solution
Verified Answer
The solutions involve the calculation of the exit Mach number as well as the total temperature and pressure of the gas at the exit. Each of these parameters requires knowledge of the initial conditions, the compressibility factor, and the application of the Fanno line equation.
1Step 1: Calculate the parameters for inlet condition
First, we need to calculate the compressibility factor \(Z\) at inlet condition, using the given information. In this case, \(Z = \gamma M_{1}^2 = 1.4 \times (2.0)^2 = 5.6\). Next, we can calculate the total temperature at inlet, \(T_{01}\) using the formula \(T_{01} = T_{1}Z = 250K \times 5.6 = 1400K\). Similarly, the total pressure at inlet, \(p_{01}\), can be calculated as \(p_{01} = p_{1}Z = 25kPa \times 5.6 = 140kPa.\)
2Step 2: Establish the Fanno line equation
The Fanno line equation for adiabatic flow given by: \(Z - 1 = \frac{4fLD_{h}}{D \pi^2} \left(M^2_{2} - 1\right)\). Here \(f = C_{f} = 0.005\) is the friction coefficient, \(L = 10.262\times D_{h}\) is the length of the duct, and \(D\) represents diameter of the duct, and \(Z\) is the compressibility factor we calculated earlier. We can substitute these values into the equation to solve for \(M_{2}\), the exit Mach number.
3Step 3: Calculate the exit Mach number
Upon substituting the values into the Fanno line equation, you will obtain a quadratic equation. Solve for \(M_{2}\), considering only the physically meaningful solution.
4Step 4: Determine the exit parameters
To compute \(T_{12}\), and \(p_{12}\), the total temperature and pressure at the exit respectively, we use the formulas: \(T_{12} = T_{01} / Z_2\) and \(p_{12} = p_{01} / Z_2\), where \(Z_2 = \gamma M_{2}^2\).
5Step 5: Final checks
Finally, evaluate your solutions for \(M_{2}\), \(T_{12}\), and \(p_{12}\). Ensure they are within logical bounds. This means \(M_{2}\) should be real and positive and \(T_{12}\), \(p_{12}\) values should not be less than absolute zero or the initial pressure respectively.
Key Concepts
Mach Number CalculationFanno Line EquationCompressibility FactorTotal Temperature and PressureFriction Coefficient in Ducts
Mach Number Calculation
In fluid dynamics, the Mach number is a crucial parameter that indicates the speed of a flow relative to the speed of sound in the medium. A Mach number:
- Less than 1 indicates subsonic flow.
- Exactly 1 is sonic flow.
- Greater than 1 signifies supersonic flow.
Fanno Line Equation
The Fanno line equation describes the relationship between various flow properties in an adiabatic flow within a duct where friction is present. It is expressed mathematically as: \[Z - 1 = \frac{4fLD_{h}}{D \pi^2} (M^2_{2} - 1)\]This equation accounts for:
- The compressibility factor \(Z\).
- The friction coefficient \(f\).
- The duct length \(L\) and diameter \(D\).
- The change in the square of the Mach number \(M^2\).
Compressibility Factor
The compressibility factor \(Z\) is a dimensionless number that gives insights into how the physical behavior of a real gas deviates from that of an ideal gas. In the context of adiabatic flow, often assuming perfect gases, it is calculated at the inlet as: \[Z = \gamma M^2\] where \(\gamma\) is the specific heat ratio and \(M\) is the Mach number. The compressibility factor helps in bridging the inlet and outlet states in a duct flow, reflecting the effects of compressibility. For gases with high Mach numbers, \(Z\) becomes significant, reflecting substantial changes in temperature, pressure, and density.
Total Temperature and Pressure
Total temperature and total pressure are pivotal in analyzing duct flow problems. They signify state functions that remain constant along an ideal streamline in adiabatic flows but alter due to friction in real scenarios.
- Total temperature at the inlet is calculated as: \[T_{01} = T_{1} Z\], reflecting how friction impacts energy dissipation.
- Likewise, total pressure is \[p_{01} = p_{1} Z\], showing the impact of velocity and pressure changes.
Friction Coefficient in Ducts
The friction coefficient \(C_f\) is an essential parameter in determining how flow behaves in a duct. Defined as a measurement of resistance to flow due to the duct surface's roughness and other factors, it has significant effects on the flow parameters.
- A higher \(C_f\) means more energy is lost to friction, translating into reduced velocity or higher pressure drop.
- In adiabatic flows, the friction coefficient takes center stage in the Fanno line equation, impacting the calculation of parameters like Mach number at exit.
Other exercises in this chapter
Problem 46
Consider an insulated constant-area duct. The average wall friction coefficient is \(C_{1}=0.005\). Assuming the length-to-(hydraulic) diameter ratio for the du
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An inviscid perfect gas flows through a constant-area duct that is subject to heat transfer. The ratio of heat transfer to mass flow rate is \(q=250 \mathrm{~kJ
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Consider the flow of perfect gas in a duct with \(T_{2} / T_{1}=1.01, p_{2} / p_{1}=1.038\) and \(M_{2} / M_{1}=0.88\). Assuming gas properties are \(\gamma=1.4
View solution Problem 50
In a Fanno flow problem with a supersonic inlet Mach number of \(M_{1}=2.0\), a normal shock appears at \(M_{x}=\) 1.2. Assuming the average friction coefficien
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