Problem 48
Question
If \(n\) is a positive integer, show that \(\left(\begin{array}{l}n \\\ 0\end{array}\right)-\left(\begin{array}{l}n \\\ 1\end{array}\right)+\left(\begin{array}{l}n \\\ 2\end{array}\right)-\cdots+(-1)^{n}\left(\begin{array}{l}n \\\ n\end{array}\right)=0\)
Step-by-Step Solution
Verified Answer
Based on the binomial theorem, \(\binom{n}{0} - \binom{n}{1} + \binom{n}{2} - \dots + (-1)^n \binom{n}{n} = 0\).
1Step 1 - Understanding the Binomial Coefficients
Recall that the binomial coefficient \(\binom{n}{k}\) is defined as the number of ways to choose \k\ elements from \ elements. Mathematically, \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
2Step 2 - Recognizing Alternating Sum
Given the expression \(\binom{n}{0} - \binom{n}{1} + \binom{n}{2} - \dots + (-1)^n \binom{n}{n} = 0\), we notice that it involves an alternating sum of binomial coefficients.
3Step 3 - Using the Binomial Theorem
The binomial theorem states that \((1 + (-1))^n = \sum_{k=0}^{n} \binom{n}{k} (-1)^k = (1 - 1)^n \).
4Step 4 - Simplifying Using Binomial Theorem
Since \(1 - 1 = 0\), we have \( (0)^n = 0 \). Therefore, \sum_{k=0}^{n} \binom{n}{k} (-1)^k = 0\.
5Step 5 - Concluding the Proof
Recognize that the sum \sum_{k=0}^{n} \binom{n}{k} (-1)^k\ equals the given expression \(\binom{n}{0} - \binom{n}{1} + \binom{n}{2} - \dots + (-1)^n \binom{n}{n}\), which confirms that it is indeed equal to 0.
Key Concepts
binomial coefficientalternating sumcombinatoricsproof techniques
binomial coefficient
The binomial coefficient, often denoted as \(\binom{n}{k}\), represents the number of ways to choose \(k\) elements from a set of \(n\) elements. It is a fundamental concept in combinatorics and can be calculated using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] Here, \(n!\) (n factorial) is the product of all positive integers up to \(n\), and \(k!\) is the product of all positive integers up to \(k\). For example, \(\binom{5}{2} = \frac{5!}{2!(5-2)!} = 10\). Binomial coefficients have many uses in mathematics, particularly in expansions, probability, and algebra.
alternating sum
An alternating sum is a sequence of numbers where the signs of the terms alternate between positive and negative. In the context of binomial coefficients, the alternating sum can be written as: \(\binom{n}{0} - \binom{n}{1} + \binom{n}{2} - \binom{n}{3} + ... + (-1)^n \binom{n}{n}\). This type of sum appears frequently in mathematical proofs and combinatorial identities. An alternating sum is particularly useful because it can simplify complex expressions and expose underlying patterns. In our exercise, the alternating sum of binomial coefficients results in zero, providing a strong proof related to the binomial theorem.
combinatorics
Combinatorics is a branch of mathematics dealing with counting, arrangement, and combination of objects. It forms the basis for many mathematical proofs and concepts, including the binomial theorem, binomial coefficients, and permutations. Key areas within combinatorics include:
- Combinations: Selecting items from a set where order does not matter.
- Permutations: Arranging items from a set where order matters.
- Partitions: Dividing a set into non-overlapping subsets.
proof techniques
Proof techniques are methods used to establish the truth of mathematical statements. There are several ways to approach proofs, each suitable for different types of problems. Some common techniques include:
- Direct Proof: Proving a statement by straightforward logical reasoning.
- Contradiction: Assuming the opposite of what needs to be proven and showing it leads to an inconsistency.
- Induction: Proving a base case and then showing that if one case holds, the next one must hold too.
- Combinatorial Proof: Using combinatorial arguments to show that two expressions count the same set in different ways.
Other exercises in this chapter
Problem 47
If \(n\) is a positive integer, show that \(\left(\begin{array}{l}n \\\ 0\end{array}\right)+\left(\begin{array}{l}n \\\ 1\end{array}\right)+\cdots+\left(\begin{
View solution Problem 47
A sequence is defined recursively. List the first five terms. \(a_{1}=\sqrt{2} ; \quad a_{n}=\sqrt{2+a_{n-1}}\)
View solution Problem 48
A sequence is defined recursively. List the first five terms. \(a_{1}=\sqrt{2} ; \quad a_{n}=\sqrt{\frac{a_{n-1}}{2}}\)
View solution Problem 49
Use a graphing utility to find the sum of each geometric sequence. $$ \sum_{n=1}^{15}\left(\frac{2}{3}\right)^{n} $$
View solution