Problem 48
Question
For the following problems, use the zero-factor property to solve the equations. $$ (x+5)(x+4)=0 $$
Step-by-Step Solution
Verified Answer
Answer: The solutions for x are -5 and -4.
1Step 1: Identify the factors
In this equation, the factors are (x+5) and (x+4).
2Step 2: Apply the zero-factor property
To apply the zero-factor property, set each factor equal to zero:
(x+5)=0 and (x+4)=0
3Step 3: Solve for x in each equation
Solve for x in the first equation:
x+5=0
x=-5
Solve for x in the second equation:
x+4=0
x=-4
4Step 4: Write the final solution
The solutions for x are -5 and -4. This can be expressed as:
x = {-5, -4}
Key Concepts
Solving Quadratic EquationsFactoringRoots of Equations
Solving Quadratic Equations
Solving quadratic equations is a core skill in algebra. A quadratic equation is an equation of the form \(ax^2 + bx + c = 0\). Quadratic equations can have two solutions because they are degree 2 polynomials. There are several methods to solve these equations, including:
- Factoring
- Using the quadratic formula
- Completing the square
Factoring
Factoring is a powerful tool used to simplify polynomial expressions. When solving quadratic equations by factoring, we aim to express the quadratic equation in a product of two binomials. Consider a quadratic equation written as \((x + m)(x + n) = 0\). The task is to find two numbers, \(m\) and \(n\), such that when multiplied they give \(c\), and when added, they give \(b\).
For example, the expression \((x+5)(x+4)=0\) is already factored, with \(m=5\) and \(n=4\). This method allows us to use the Zero-Factor Property to find the variable's value by setting each factor to zero. When factors are correctly identified, the quadratic equation can be split into linear equations that are much easier to solve.
For example, the expression \((x+5)(x+4)=0\) is already factored, with \(m=5\) and \(n=4\). This method allows us to use the Zero-Factor Property to find the variable's value by setting each factor to zero. When factors are correctly identified, the quadratic equation can be split into linear equations that are much easier to solve.
Roots of Equations
Roots, or solutions, of a quadratic equation are the values of \(x\) that satisfy the equation \(ax^2 + bx + c = 0\). In simpler terms, the roots are the points where the graph of the equation intersects the x-axis. For a factored quadratic equation, such as \((x+5)(x+4)=0\), the roots can be easily determined using the Zero-Factor Property.
The Zero-Factor Property states that if a product of two terms is zero, then at least one of the terms must be zero. Therefore, set each factor equal to zero and solve for \(x\).
The Zero-Factor Property states that if a product of two terms is zero, then at least one of the terms must be zero. Therefore, set each factor equal to zero and solve for \(x\).
- For \(x+5=0\), subtract 5 from both sides to get \(x=-5\).
- For \(x+4=0\), subtract 4 from both sides, resulting in \(x=-4\).
Other exercises in this chapter
Problem 48
For the following problems, solve the equations, if possible. $$ b^{2}=4 $$
View solution Problem 48
For the following problems, solve each of the quadratic equations using the method of extraction of roots. $$ (x-1)^{2}=4 $$
View solution Problem 49
For the following problems, solve the equations using the quadratic formula. $$ (b-6)^{2}=8 $$
View solution Problem 49
For the following problems, solve the equations, if possible. $$ b^{2}=1 $$
View solution