Problem 48
Question
For the following exercises, simplify the rational expression. \(\frac{\frac{2 x}{3}+\frac{4 x}{7}}{\frac{x}{2}}\)
Step-by-Step Solution
Verified Answer
The simplified form is \(\frac{52}{21}\).
1Step 1: Simplify the Numerator
To simplify the numerator, find a common denominator for the fractions \(\frac{2x}{3}\) and \(\frac{4x}{7}\). The common denominator is 21. Rewrite each fraction with this common denominator: \(\frac{2x}{3} = \frac{14x}{21}\) and \(\frac{4x}{7} = \frac{12x}{21}\). Add these to get \(\frac{26x}{21}\).
2Step 2: Rewrite the Expression
Replace the original numerator in the expression with the simplified form: \(\frac{\frac{26x}{21}}{\frac{x}{2}}\).
3Step 3: Simplify by Dividing Fractions
To simplify \(\frac{\frac{26x}{21}}{\frac{x}{2}}\), multiply by the reciprocal of \(\frac{x}{2}\). So it becomes \(\frac{26x}{21} \times \frac{2}{x}\).
4Step 4: Perform Multiplication
Multiply the numerators: \(26x \times 2 = 52x\). Multiply the denominators: \(21 \times x = 21x\). This gives \(\frac{52x}{21x}\).
5Step 5: Cancel Common Factors
Cancel out \(x\) in the numerator and denominator: \(\frac{52x}{21x} = \frac{52}{21}\). This is the simplified form.
Key Concepts
SimplificationCommon DenominatorsFraction OperationsReciprocal Multiplication
Simplification
Simplification of rational expressions involves reducing them to their simplest form. A rational expression is made up of a ratio of two polynomials. To simplify such expressions efficiently, identify and eliminate any common factors from the numerator and the denominator. This process involves:
Simplification makes further algebraic manipulation more manageable.
- Combining like terms where similar variables and powers are present
- Performing arithmetic operations
Simplification makes further algebraic manipulation more manageable.
Common Denominators
Finding a common denominator is crucial when adding or subtracting fractions, as it allows these operations to be performed on a consistent basis. A common denominator is essentially a shared multiple of the denominators involved. For the fractions \(\frac{2x}{3}\) and \(\frac{4x}{7}\), the least common denominator is 21.
- Rewrite each fraction so that they have this common denominator
- Ensure that the equivalent expressions retain the same value as the original fractions
- This adjustment allows for straightforward addition or subtraction of the numerators
Fraction Operations
Performing operations with fractions—be it addition, subtraction, multiplication, or division—follows specific rules. For expressions like \(\frac{\frac{26x}{21}}{\frac{x}{2}}\), understanding these operations becomes key.
- Addition/Subtraction: Only possible with common denominators
- Multiplication: Multiply numerators together and denominators together
- Division: Multiply by the reciprocal of the divisor
Reciprocal Multiplication
Reciprocal multiplication transforms division problems into multiplication ones, aiding in simplifying rational expressions. To find the reciprocal of a fraction, swap its numerator and denominator. For \(\frac{x}{2}\), the reciprocal is \(\frac{2}{x}\).
By multiplying \(\frac{26x}{21}\) by the reciprocal \(\frac{2}{x}\), you effectively handle operations that require division. This step is essential since multiplying instead of dividing is generally more intuitive and aligns with the rules of fraction operations:
By multiplying \(\frac{26x}{21}\) by the reciprocal \(\frac{2}{x}\), you effectively handle operations that require division. This step is essential since multiplying instead of dividing is generally more intuitive and aligns with the rules of fraction operations:
- Transforms complex division into straightforward multiplication
- Allows simplification by cancellation of similar terms
Other exercises in this chapter
Problem 47
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For the following exercises, simplify the expression. \(6+12 b-3 \times 6 b\)
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For the following exercises, factor the polynomials. \(9 y(3 y-13)^{\frac{1}{5}}-2(3 y-13)^{\frac{6}{5}}\)
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For the following exercises, multiply the polynomials. \((9 m+4 n-1)(2 m+8)\)
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